Find the greatest common factor. In this case it is 3. Divide each group by 3.
15÷3=5 quarters
30÷3=10 dimes
48÷3=16 nickels
Next count them by the coin's value:
5 × 0.25 = $1.25
10 × 0.10 = $1
16 × 0.05 = $0.80
Add them up:
= $3.05 in each group and there are three groups.
So, the greatest number of groups that he can make is 3; there will be 5 quarters, 10 dimes, and 16 nickels in each group, which is worth $3.05 in each group.
R=17
5(17-2)=75
5(15)=75
75=75
Answer:
x=10
y=-3
Step-by-step explanation:
3x + 5y= 15...eqn. 1
2x + 4y= 8...eqn. 2
multiply eqn. 1 by 2 and eqn. 2 by 3
6x + 10y = 30...eqn. 3
<u>6x</u><u> </u><u>+</u><u> </u><u>12y</u><u> </u><u>=</u><u> </u><u>24...eqn. 4</u>
0 - 2y = 6
divide both sides by the coefficient of y which is -2
<u>- 2y</u> = <u>6</u>
- 2 -2
y= -3
Put y= -3 into eqn. 1
3x + 5(-3) = 15
3x - 15 = 15
3x =15 + 15
<u>3x</u> =<u> 30</u>
3 3
x = 10
Therefore X= 10 and Y= -3
So, since the student makes $30 each week, we can disregard the number of hours.
So, we can model this situation by the following equation
9.5h+30
So, if he works 10.25 hrs (15 minutes = .25 of 1 hr) we just plug that number in

Since it's money we round to the nearest cent
So he will make $127.28 Next week
Answer:
g is decreasing for all x less than or equal to -1
Step-by-step explanation:
The graph of the function y = |x| looks like a "vee."
g(x) = |x + 1| - 7 moves that graph 1 unit to the <u>left</u><em> </em>(I know, it looks backwards!) and down 7 units. See attached image.
Function g(x) is decreasing for all
.