All categories

3 years ago

Find a formula for the nth term in this arithmetic sequence. a1=0, a2=0.5, a3=1, a4=1.5

Mathematics

1 answer:

MrRissso [65]3 years ago

6 0

Answer:

nth term is;

0.5n-0.5

Step-by-step explanation:

As we can see, the first term is 0

The common difference is 0.5-0= 1-0.5 = 1.5-1 = 0.5

Formula for nth term of an arithmetic sequence is;

a + (n-1)d

So we have

0 + (n-1) 0.5

= 0.5n-0.5

You might be interested in

Can someone please help me with numbers 1, a, b, c, 2, a, b, c

algol [13]

Thank you thank you very much

7 0

2 years ago

Write a polynomial that fits the description:

8090 [49]

4x^5 + 3x + 1...the ^5 makes it a fifth degree....and the leading coefficient is 4

5 0

3 years ago

Read 2 more answers

Simplify the following expression.<br><br>10|3 - 7| + 24<br><br>

weeeeeb [17]

Answer:

Step-by-step explanation:

The answer is 0 due to using PEMDAS

5 0

3 years ago

Jennifer earns $8.50 per hour for regular work time and $10.50 per hour for overtime. Last week, Jennifer worked 43 hours of reg

allochka39001 [22]

Answer:

$433.84

Step-by-step explanation:

First, find the amount of money Jennifer earned for regular work time:

8.50 x 43 = 365.50

Then, find the amount of money Jennifer earned for overtime work:

10.50 x 6.5 = 68.25

Finally, add them:

365.50 + 68.25 = 433.75

3 0

2 years ago

Train a travel 175 miles in a four hours. for train b y=43.5x represents its rate of speed over the same 4 hours which train tra

stepan [7]

Answer:

Train A is faster by a factor of 1.01

Step-by-step explanation:

Given:

Train A:

Distance = 175 Miles

Time = 4 Hours

Train B:

y=43.5x

To Find:

which train travels at a faster rate in by what factor =?

Solution:

The speed of the train A = $\frac{Distance}{time}$

The speed of train A = $\frac{175}{4}$

The speed of train A = 43.75 miles per hour

Speed of the train B is the slope of the given line

The standard equation of the slope of the line is

y = mx+b

where m is the slope

and we are given with

y = 43.5x

So comparing with the standard equation

m = 43.5

Hence the speed of train B is 43.5 miles per hours

Train A travels faster

$Rate =\frac{\text{speed of train A}}{\text {Speed of train B}}$

$rate = \frac{43.75}{43.5}$

rate =1.01

7 0

3 years ago