Okay.. well did you try to do it on your own at least ? I help you, but what do you know already so we can go on from there.
Answer:
a) 0.70
b) 0.82
Step-by-step explanation:
a)
Let M be the event that student get merit scholarship and A be the event that student get athletic scholarship.
P(M)=0.3
P(A)=0.6
P(M∩A)=0.08
P(not getting merit scholarships)=P(M')=?
P(not getting merit scholarships)=1-P(M)
P(not getting merit scholarships)=1-0.3
P(not getting merit scholarships)=0.7
The probability that student not get the merit scholarship is 70%.
b)
P(getting at least one of two scholarships)=P(M or A)=P(M∪A)
P(getting at least one of two scholarships)=P(M)+P(A)-P(M∩A)
P(getting at least one of two scholarships)=0.3+0.6-0.08
P(getting at least one of two scholarships)=0.9-0.08
P(getting at least one of two scholarships)=0.82
The probability that student gets at least one of two scholarships is 82%.
1 /5 = 0 . 2
45 * . 2 = 9
Hope this helped :)
Answer:
I believe the answer is D, but I'm not entirely sure.
Step-by-step explanation:
The Pythagorean theorem is A squared times B squared equals C squared. So your closest statement is D.
Let me know if I'm wrong
