The min or max of a parabola/quadratic function is the vertex
for
y=a(x-h)²+k
the vertex is (h,k)
so
vertex/min is at (-1,2)
h=-1
k=2
y=a(x-(-1))²+2
y=a(x+1)²+2
find a
given, (2,20) is on the graph
20=a(2+1)²+2
20=a(3)²+2
20=9a+2
minus 2 both sides
18=9a
divide by 9
2=a
y=2(x+1)²+2 is da equation
3rd one
f(x)=2(x+1)²+2
Answer: L=13
Step-by-step explanation: Multiply your eight and five...
5•8=40
Then...Divide forty by two-hundred-fifty...
250/40=13.
You ALWAYS want to check your answer by multiplying to see if you are absolutely correct.
So...5•8•13=250.
Your answer is...Length = 13.
I hope this helps you!
Given that,
The diameter of a semicircle is 2 mm.
To find,
The area of the semicircle.
Solution,
Radius of semicircle, r = 1 mm
The area of a semicircle is given by the formula as follow :
So, the area of the semicircle is 
.
