Answer:
0.9009
Step-by-step explanation:
Let X be the event that Current will flow
Let Y be the event that the first relay which is 1 is closed
Thus, we can say that every element of Y is in X, but X possesses more elements. Thus, Y ⊂ X.
Thus, we can say that;
P(X ∩ Y) = P(Y)
Thus, given that current flowed, the probability that relay 1 functioned will be expressed as;
P(Y | X) = (P(Y ∩ X))/P(X)
From earlier, we saw that P(X ∩ Y) = P(Y). Thus;
P(Y | X) = P(Y)/P(X)
From the question, P(Y) = 0.9
Since there are 3 relays, then we have;
P(X) = 1 - 0.1³ = 0.999
Thus;
P(Y | X) = 0.9/0.999
P(Y | X) = 0.9009
No. 4^2 + 8^2 or 16 + 64 is 80, and the hypotenuse, 12 (144) is not 80.
The lines mean that the number is going to become positive. |-178| will become positive meaning it will become= |178|
I think It is 2. it makes the most sense to me
Answer:
422mins and 8sec
Step-by-step explanation:
အားလုံးကိုပေါင်းလိုက်
