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3 years ago

Use the Exterior Angle Inequality Theorem to list all of the angles that measure less than the measure of Angle 1

Mathematics

1 answer:

11111nata11111 [884]3 years ago

6 0

Answer:

Step-by-step explanation:

Since, angle 1 is an exterior angle of ΔABE,

m∠1 > m∠3 and m∠4

Since, angle 1 is an exterior angle of ΔABD,

m∠1 > m∠5

Since, angle 1 is an exterior angle of ΔABC,

m∠1 > m∠7 and m∠8

Therefore, ∠1 is greater than ∠3, ∠5, ∠7 and ∠8.

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A rectangular tank of 12 m long, 11 m wide and 13 m deep held

Damm [24]

Answer:

The tanks volume is 1716 m.

Step-by-step explanation: I am not sure about the water.

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3 years ago

Which is the correct way to solve the given equation

Karolina [17]

Option 2. $x = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}$ shows the correct way to use the quadratic formula to solve the given equation.

Step-by-step explanation:

Step 1:

For an equation of the form $ax^{2} +bx+c=0$ the solution is $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ .

Here a is the coefficient of $x^{2}$ , b is the coefficient of x and c is the constant term.

$x^{2} -4x=21$ can also be written as $x^{2} -4x-21=0.$

Comparing $x^{2} -4x-21=0$ with $ax^{2} +bx+c=0$ , we get that a is 1, b is -4 and c is -21.

To get the solution, we substitute the values of a, b, and c in $x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ .

Step 2:

Substituting the values, we get

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}= \frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.$

$\frac{-(-4) \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)} = \frac{4 \pm \sqrt{(-4)^{2}-4 (1)(-21)}}{2 (1)}.$

This is option 2.

7 0

3 years ago

consider that 15(1.055)^x shows the balance in a savings account over time with no additional deposits or withdrawals. Which sta

riadik2000 [5.3K]

Answer:

I really don't know but I will give you a tip on where to find it weegy.com

Step-by-step explanation:

4 0

3 years ago

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Really Need Help Quick Please! Must turn this in . Please show work. Brainliest answer will be awarded to quickest, correct answ

Anestetic [448]

X = slide height
sine (35) = opp / hypotenuse
sine (35) = x / 4.1

x = 0.57358 * 4.1
x = 2.351678 meters
Okay to the nearest meter it is 2

5 0

3 years ago

Which pair of equations generates graphs with the same vertex?

puteri [66]

Answer:

The pair of equations that generates graphs

with the same vertex is :

y = –4x² ; y = 4x²

Step-by-step explanation:

A quadratic function can be written in the form f(x) = a(x – h)² + k, where a, h, and k are constants.

It’s graph is a parabola which has a vertex at (h, k).

• The graph of the equation y = – (x + 4)² = – [x – (–4)]² + 0

has a vertex at (-4 , 0).

On the other hand ,The graph of the equation y = (x – 4)² = (x – 4)² + 0

has a vertex at (4 , 0).

Therefore , the two equations generate graphs with different vertices.

• The graph of the equation y = –4x² = –4 (x –0)² + 0

has a vertex at (0 , 0).

On the other hand ,The graph of the equation y = 4x² = 4 (x –0)² + 0

has a vertex at (0 , 0).

Therefore , the two equations generate graphs with the same vertex.

• The graph of the equation y = – x² – 4 = – (x – 0)² + (– 4)

has a vertex at (0 , -4).

On the other hand ,The graph of the equation y = x² + 4 = (x – 0)² + 4

has a vertex at (0 , 4).

Therefore , the two equations generate graphs with different vertices.

• The graph of the equation y = (x – 4)² = (x – 4)² + 0

has a vertex at (4 , 0).

On the other hand ,The graph of the equation y = x² + 4 = (x – 0)² + 4

has a vertex at (0 , 4).

Therefore , the two equations generate graphs with different vertices.

6 0

1 year ago

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