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3 years ago

13

I have test corrections and I'm having trouble figuring out what I did wrong. I just need how to get the answer and I should be

able to figure it out.
Find Angle ABC

1 answer:

Mrrafil [7]3 years ago

3 0

Answer:

The answer is 68 :D

Step-by-step explanation:

(Just read the whole comment ;P)

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the sum of −2x2 + x + 31 and 3x2 + 7x − 8 can be written in the form ax2 + bx + c, where a, b, and c are constants. What is the

Kitty [74]

Answer:

$a+b+c=32$

Step-by-step explanation:

we have

$(-2x^{2} +x+31)+(3x^{2}+7x-8)$

Adds the terms

Group terms that contain the same variable

$(-2x^{2}+3x^{2})+(x+7x)+(31-8)$

Combine like terms

$(x^{2})+(8x)+(23)$

where

$a=1,b=8,c=23$

therefore

$a+b+c=1+8+23=32$

8 0

3 years ago

What is 2(-9x-4y-7) simplified

Setler79 [48]

-18x-8y-14 because you need to distribute the digits

4 0

2 years ago

Suppose 52% of the population has a college degree. If a random sample of size 563563 is selected, what is the probability that

amm1812

Answer:

The value is $P(| \^ p - p| < 0.05 ) = 0.9822$

Step-by-step explanation:

From the question we are told that

The population proportion is $p = 0.52$

The sample size is n = 563

Generally the population mean of the sampling distribution is mathematically represented as

$\mu_{x} = p = 0.52$

Generally the standard deviation of the sampling distribution is mathematically evaluated as

$\sigma = \sqrt{\frac{ p(1- p)}{n} }$

=> $\sigma = \sqrt{\frac{ 0.52 (1- 0.52 )}{563} }$

=> $\sigma = 0.02106$

Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as

$P(| \^ p - p| < 0.05 ) = P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 ))$

Here $\^ p$ is the sample proportion of persons with a college degree.

So

$P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )$

Here

$\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(Z < 2.37 ) - P(Z < -2.37 )$

From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is

$P(Z < 2.37 ) = 0.9911$

and

$P(Z < - 2.37 ) = 0.0089$

So

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) =0.9911-0.0089$

=> $P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = 0.9822$

=> $P(| \^ p - p| < 0.05 ) = 0.9822$

3 0

3 years ago

Given: r is inversely proportional to s. If r = 16 when s = 3, then write the formula for the relation between r and s.

riadik2000 [5.3K]

Answer:

B

Step-by-step explanation:

Given that r is inversely proportional to s then the equation relating them is

r = $\frac{k}{s}$ ← k is the constant of proportion

To find k use the condition r = 16 when s = 3

k = rs = 16 × 3 = 48

r = $\frac{48}{s}$ ← equation of variation → B

3 0

2 years ago

Convert 0.0002 ug to mg:<br> Please help

Ksju [112]

1 ug = 0,001 mg

0,0002 ug= x

x= (0,0002×0,001)/1

x= 2e-7

8 0

3 years ago