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Naddika [18.5K]
3 years ago
7

B. Prove the following using indirect proof.

Mathematics
1 answer:
iren [92.7K]3 years ago
8 0

Answer:

jsjsusjsksksisidjjdsksjks

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Simplify (7+5)^2 divided by 4 x 3 + 9
MaRussiya [10]
((7 + 5)^2) / (4 * 3 + 9) =
(12^2) / (12 + 9) =
144 / 21 reduces to 48/7 or 6 6/7

7 0
4 years ago
Which of the following is an example of a proper fraction?<br> A.7/6<br> B.3/4<br> C.4/4<br> D.4/3
statuscvo [17]

Answer: B

Step-by-step explanation:

A proper fraction is when a fraction has the numeration less than the denominator

3 0
3 years ago
At present the sum of Monica's age and daughter's age is 44 years. . After 2 years Monica's age will be three times that if her
sergeinik [125]

Answer:

Monica's age = 34 years

Her daughter's age = 10 years

Step-by-step explanation:

Let Monica's age = x

Let her daughter'sage = y

x + y = 44   -------> equ 1

After 2 years:

Monica's age = x + 2

Her daughter's age = y + 2

x + 2 = 3 * (y+2)

x + 2 = 3y + 6

      x = 3y + 6 -2

      x = 3y + 4

Put x value in equ 1:

    3y + 4 + y = 44

            4y = 44 - 4

             4y = 40

               y = 40/4

               y = 10

x = 44 -10

x = 34

7 0
3 years ago
Read 2 more answers
Kiran got 99 marks in Math, 69 mark in English and 91 in science. Another student Surya got 92 marks in Maths 33 in English and
statuscvo [17]

Answer:

Total marks = 468

Step-by-step explanation:

to find their total marks, you should simply find the sum of all the marks scored by Kiran and Surya in all subjects. That is done as follows:

99 + 69 + 91 + 92 + 33 + 84 =  468

4 0
4 years ago
Write a function for the situation discribed and find the value after 5 yrs. A $12,500 car depreciates 9% each year. Please help
sweet [91]
\bf \qquad \textit{Amount for Exponential Decay}\\\\&#10;A=P(1 - r)^t\qquad &#10;\begin{cases}&#10;A=\textit{accumulated amount}\\&#10;P=\textit{initial amount}\to &12500\\&#10;r=rate\to 9\%\to \frac{9}{100}\to &0.09\\&#10;t=\textit{elapsed time}\\&#10;\end{cases}&#10;\\\\\\&#10;A=12500(1-0.09)^t\implies A=12500(0.91)^t&#10;\\\\\\&#10;\textit{after 5 years t = 5}\qquad A=12500(0.91)^5

and surely you know how much that is.
5 0
4 years ago
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