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maks197457 [2]
3 years ago
6

What is the value of 7 in the number 8975

Mathematics
2 answers:
anyanavicka [17]3 years ago
7 0
8975
^ 7 is on tens
astraxan [27]3 years ago
5 0

Answer:

70?

Step-by-step explanation:

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I'm stuck on another question 5 4/5 + (-3 2/7)
anyanavicka [17]

So that would be the same thing as 5 4/5 - 3 2/7

Put them in mixed fractions to become 29/5 - 23/7

Multiply one side by 7 and one side by 5 to get the same denominator  

203/35 - 115/35

Now subtract the numerators to get

88/35

Or if they want it inixed numbers then 2 18/35

5 0
3 years ago
Read 2 more answers
Express your answer in scientific notation. 4.9\cdot 10^{5} - 5.8 \cdot 10^{4} =4.9⋅10 5 −5.8⋅10 4 =4, point, 9, dot, 10, start
tatyana61 [14]

Answer:

4.32*10^{5}

Step-by-step explanation:

Given the expression 4.9*10^{5}-5.8*10^{4}, to solve the expression, we need to write both scientific notation to the same power of 10.

5.8*10^{4} is \ expressed\  as \ 0.58*10^{5}

The expression above becomes 4.9*10^{5}-0.58*10^{5}. On taking the difference;

4.9*10^{5}-0.58*10^{5}\\= (4.9-0.58)*10^{5} \\= 4.32*10^{5}

The final expression gives the right answer

4 0
3 years ago
If the radius of the base is 2, and the height is 4, what is the volume of the cylinder?
MAVERICK [17]
givens
pi = 3.14
r = 2
h = 4

Formula
v = pi r^2 h

Sub and Solve
V = 3.14 * 2^2 * 4
V = 3.14 * 4 * 4
V = 3.14 * 16
V = 50.24

4 0
3 years ago
Read 2 more answers
The radius r(t)r(t)r, (, t, )of the base of a cylinder is increasing at a rate of 111 meter per hour and the height h(t)h(t)h, (
sp2606 [1]

Answer:

The volume is decreasing at a rate 20π cubic meter per hour.

Step-by-step explanation:

We are given the following in the question:

The radius is increasing at a rate 1 meter per hour.

\dfrac{dr}{dt} = 1\text{ meter per hour}                

The height is decreasing at a rate 4 meter per hour  

\dfrac{dh}{dt} = -4\text{ meter per hour}

At an instant time t,

r = 5 meter

h = 8 meters

Volume of cylinder =

\pi r^2 h

where r is the radius and h is the height of the cylinder.

Rate of change of volume is given by:

\dfrac{dV}{dt} = \dfrac{d(\pi r^2 h)}{dt}\\\\\dfrac{dV}{dt} = 2\pi rh\dfrac{dr}{dt} + \pi r^2\dfrac{dh}{dt}

Putting all the values we get,

\dfrac{dV}{dt} = 2\pi (5)(8)(1) + \pi (5)^2(-4)\\\\\dfrac{dV}{dt} = 80\pi - 100\pi = -20\pi \approx -62.8

Thus, the volume is decreasing at a rate 20π cubic meter per hour or 62.8 cubic meter per hour.      

3 0
3 years ago
Halp me on my math plz
liubo4ka [24]
Post a better quistion
6 0
3 years ago
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