All categories

3 years ago

What are the domain and range of f(x)=-37

Mathematics

1 answer:

balandron [24]3 years ago

3 0

Answer: Domain: All real numbers. Range: y=-37

Step-by-step explanation: The function of f(x)=-37 is a horizontal line that goes from negative infinity to positive infinity. The domain can be any number since there is no limit on what the x value can be. The range will always be y=-37 because no matter what x will equal, y will always be equal to -37 in the function of f(x)=-37.

You might be interested in

Pls help with these questions I can give brainliest thank you all! 9 a and b

nata0808 [166]

Answer:

A. 8 1/4 * 11 1/2 * 14=1328 1/4 ft^2

8 1/4 height times 11 1/2 width times 14 in length equals 1328 1/4 feet squared

B. 8 1/4 * 14 1/2 * 14=1674 3/4

8 1/4 height times 11 1/2 width plus 3 so 14 1/2 width times 14 equals 1674 3/4 feet squared

Step-by-step explanation:

7 0

2 years ago

How many ordered pairs do you need in order to use the Slope Formula?

Fantom [35]

You only need two separate ordered pairs for the slope formula

8 0

2 years ago

You have two exponential functions. One function has the formula g(x) = 5 x . The other function has the formula h(x) = 5-x . Wh

AVprozaik [17]

Given the exponential functions $g(x)= 5^{x}$ and $h(x)= 5^{-x}$

$k(x)=(g-h)(x)$
$k(x)=g(x)-h(x)
$
$k(x)= 5^{x} - 5^{-x}$
$k(x)= 5^{x} - \frac{1}{ 5^{x} }$
$k(x)= \frac{ 5^{x} 5^{x} }{ 5^{x} } - \frac{1}{ 5^{x} }$
$k(x)= \frac{ 5^{2x} }{ 5^{x} } - \frac{1}{ 5^{x} }$
$k(x)= \frac{ 5^{2x}-1 }{ 5^{x} }$

4 0

2 years ago

Read 2 more answers

a taxi rider must pay 15000 VND for 1km in the first 10km, when exceeding 10km, they will pay them 14000 VND for each subsequent

Flura [38]

Answer:

Số tien:S =150000+(x-10)14000

Step-by-step explanation:

4 0

2 years ago

A spring is hanging from a ceiling. The length L(t) (in cm) of the spring as a function of time t (in seconds) can be modeled by

Zanzabum

Answer:

L(t) = 5·sin(πt) +7

Step-by-step explanation:

The middle of the oscillation of the given function occurs when t=0. At that point, ...

L(0) = d = 7

The next maximum of the oscillation occurs when the argument of the sine function is π/2.

b·t = π/2

b = π/(2t) = π/(2·0.5) = π

At that maximum, the length is 12, so we have ...

L(0.5) = a·sin(0.5π) +7 = 12

a = 5

The function L(t) is ...

L(t) = 5·sin(πt) +7

6 0

2 years ago