If f (x) = 2x - 6 and g (x) = 5 - 2x what is the value of f (2)

GalinKa [24]

First of its y-y1 = m(x-x1)
m is the slope, what it is increasing by.
y1 is the y intercept of your pair.
X1 is the x intercept of your coordinate pair, plug them in. If you dont know slope the formula to find it is:
y2-y1/x2-x1

8 0

3 years ago

Please help me, What is the 6th term of the geometric sequence 1024, 528, 256...?

scoundrel [369]

The geometric sequence is B: 32

5 0

3 years ago

Show work and solve for √ ( 5 x − 9 ) − 1 = x.

Mandarinka [93]

sqrt (5x - 9) - 1 = x

sqrt(5x - 9) = x + 1

Square both sides:_

5x - 9 = x^2 + 2x + 1

x^2 - 3x + 10 = 0

(x - 5)(x + 2) = 0

x = 5 or -2.

Lets look for for any extraneous solutions:-

x = 5 ; sqrt (5*5-9) - 1 = sqrt16 - 1 = 3 and x = 3 (right hand side of equation)

so x = 5 is a solution

x = -2: sqrt(5*-2 - 9) - 1 = sqrt (-19) - 1 and x = -2 so this is extraneous

Answer:- One solution x = 5

4 0

4 years ago

Read 2 more answers

The table below shows the number of days that a meteorologist predicted it would be sunny and the number of days it was sunny. B

Leya [2.2K]

Answer:

570

Step-by-step explanation:

5 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

If f (x) = 2x - 6 and g (x) = 5 - 2x what is the value of f (2)​

If f (x) = 2x - 6 and g (x) = 5 - 2x what is the value of f (2)