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Yakvenalex [24]
3 years ago
10

Please help me, thank you

Mathematics
2 answers:
brilliants [131]3 years ago
8 0

Answer:

161 6/72

Step-by-step explanation:

50 5/8 plus 50 5/8 = 100 10/8 = 101 2/8

30 2/9 + 30 2/9 = 60 4/9

add them together which comes out to 161 6/?

Use LCM or least common multipule and it should come out to 161 6/72

Step-by-step explanation:

Natali5045456 [20]3 years ago
5 0

Answer:

161 6/72

Step-by-step explanation:

50 5/8 plus 50 5/8 = 100 10/8 = 101 2/8

30 2/9 + 30 2/9 = 60 4/9

add them together which comes out to 161 6/?

Use LCM or least common multipule and it should come out to 161 6/72

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Please help with Linear Function Models for 20 points, Thank you.
Bumek [7]
Y=mx+b
m=slope
b=yintercept

input points
when x=1
y=1
1=1m+b

and
x=2
y=-2
-2=2m+b
multilpy first equaiton by -1 and add to othe requation

-1=-m-b
<u>-2=2m+b +</u>
-3=m+0b

-3=m
y=-3x+b
1=-3(1)+b
1=-3+b
add 3
4=b
y=-3x+4





first blank is -3
second is 4

4 0
3 years ago
Read 2 more answers
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is P(X = 2). So:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

3 0
3 years ago
Please if you know plz tell me ;(
ANEK [815]

the images go in order to the graph

8 0
3 years ago
Don’t understand this problem
sasho [114]
The answer is AAS
As the angles are equal and there is a non included side
5 0
3 years ago
Please Help!!! :C
astraxan [27]

Answer:

10 ft

Step-by-step explanation:

Using the distance formula.

3 0
3 years ago
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