1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Yakvenalex [24]
3 years ago
10

Please help me, thank you

Mathematics
2 answers:
brilliants [131]3 years ago
8 0

Answer:

161 6/72

Step-by-step explanation:

50 5/8 plus 50 5/8 = 100 10/8 = 101 2/8

30 2/9 + 30 2/9 = 60 4/9

add them together which comes out to 161 6/?

Use LCM or least common multipule and it should come out to 161 6/72

Step-by-step explanation:

Natali5045456 [20]3 years ago
5 0

Answer:

161 6/72

Step-by-step explanation:

50 5/8 plus 50 5/8 = 100 10/8 = 101 2/8

30 2/9 + 30 2/9 = 60 4/9

add them together which comes out to 161 6/?

Use LCM or least common multipule and it should come out to 161 6/72

You might be interested in
If f(x) = 2x + 1, find f(1).
____ [38]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
Given that A=27, B=43 and c=17, solve triangle ABC to the nearest hundredth
katrin2010 [14]
When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] / <span> <span> <span> 1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) = <span> <span> <span> 0.96374829001368
Angle A = 15.475

Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span> <span> <span> <span> 154.85

</span></span></span>Finally, calculating the third angle is quite easy
Angle C =  180 - Angle (A) - Angle(B)
Angle C =  180 - 15.475 - 154.85
Angle C =  9.675

Source:
http://www.1728.org/trigtut2.htm


6 0
3 years ago
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
zhenek [66]

ANSWER

The vertical asymptotes are


\Rightarrow x=2\:or\:x=-1

<u>EXPLANATION</u>

We have

f(x)=\frac{x^2+4}{4x^2-4x-8}


For vertical asymptotes we set the denominator to zero and solve the quadratic equation;

4x^2-4x-8=0


\Rightarrow x^2-x-2=0

We split the middle term to obtain,

x^2+x-2x-2=0

\Rightarrow x(x+1)-2(x+1)=0


\Rightarrow (x-2)(x+1)=0


\Rightarrow x=2\:or\:x=-1


Therefore the vertical asymptotes are


x=2\:or\:x=-1





3 0
4 years ago
Read 2 more answers
What is 1.2 liters - 200 milliliters
jonny [76]
Well if you want to know 1.2 liters in milliliters the answer is 1200 milliliters and if you want to know 2000 milliliters in liters than the answer is 2 liters.
8 0
4 years ago
SOMEONE PLEASE HELP DUE TMM
vodka [1.7K]
Yea use a calculator
5 0
3 years ago
Other questions:
  • Defferentiate y=Insin(3x)
    8·1 answer
  • Work out and explain angle size - i will mark you as brainliest
    9·1 answer
  • Find the measures of the supplementary angles if their measures are in ratio of 11:25
    6·1 answer
  • Determine the value of r so that a line through the points (r,3) and (5,-4) has a slope of -1/2
    13·1 answer
  • You start at (8, 1). You move right 2 unit and left 3 units. Where do you end?
    8·2 answers
  • ASAP pleaaase ASAP ASAP I’ll give a brainliest
    6·1 answer
  • Jada has read 3/5 of a book. she has read 75 so far. how many pages are in the whole book?​
    11·1 answer
  • You bought a game system tor 120 and sold<br> it for $150. What is the percent increase?
    14·2 answers
  • One possible integer of x for which 1/4 &lt; k/10 &lt; 1/3 is true?
    9·1 answer
  • WILL GIVW BRANLIEST DUE TODAY thank you&gt;&gt;&gt;Three meals per day are provided by the hotel. The hotel will charge a total
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!