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3 years ago

Mr.Ramirez had $600. He saved 3/5 and spent 3/8 of the remainder

Mathematics

1 answer:

Alex73 [517]3 years ago

5 0

Answer:

$450

Step-by-step explanation:

Given function:

$600,3/5,3/8

To solve:

$600-3/5-3/8+3/5

Subtract the two terms:

$600=\frac{30}{5}$
$600$ · $\frac{3}{5}=360$

Subtract the first value by 360:

$600-360=240$

Find 3/8 of 240 and then subtract it:

$240$ · $\frac{3}{8}=90$

Combine the terms:

$360+90=450$

Therefore, Mr.Raminrez now have a total of $450..

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2. Which of the following systems of inequalities represents the graph?

Rom4ik [11]

Answer:

Option: D is the correct answer.

D) –2x + y ≥ 4

x + y < 2

Step-by-step explanation:

We are asked to find the linear inequality that represents the following graph.

Clearly from the graph we could observe that one line is dotted and the other is solid line.

i.e. one inequality is strict while the other is a inequality with equality sign.

Dashed line:

It passes through (0,2) and (2,0).

Hence, the equation of line is:

$y-2=\dfrac{0-2}{2-0}\times (x-0)\\\\\y-2=\dfrac{-2}{2}\times x\\\\y-2=-x\\\\x+y=2$

As the shaded region is towards the origin.

Hence, the inequality will be:

x+y<2.

Solid line:

The line passes through (-2,0) and (0,4).

hence equation of line is:

$y-0=\dfrac{4-0}{0-(-2)}\times (x+2)\\\\$

i.e

$y=\dfrac{4}{2}\times (x+2)\\\\y=2\times (x+2)\\\\y=2x+4\\\\-2x+y=4$

Now, as the shaded region is away from the origin hence the inequality which will be used is:

$-2x+y\geq 4$

Hence, option: D is the correct answer.

D. –2x + y ≥ 4

x + y < 2

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3 years ago

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The amount of blueberries picked, in pounds, varies directly as the number of hours worked. After

OverLord2011 [107]

Answer:

Step-by-step explanation:

3 pounds were picked per hour

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4 years ago

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Consider the parametric curve x = 2t^(3)-3t^(2)+2 and y = t^(3)-12t,-pi leq t leq pi . (a) Find the values of t (if any) where t

bagirrra123 [75]

Answer:

(a) t = ±2

(b) t ∈ {0, 1}

Step-by-step explanation:

(a) dy/dx = 0 when dy/dt = 0

dy/dt = 3t^2 -12 = 0 = 3(t -2)(t +2)

The slope is zero at t = ±2.

(b) dy/dx = (dy/dt)/(dx/dt) = undefined when dx/dt = 0

dx/dt = 6t^2 -6t = 6(t)(t -1) = 0

The slope is undefined for t ∈ {0, 1}.

(c) At t=3, dy/dx = (dy/dt)/(dx/dt) = 3(3-2)(3+2)/(6(3)(3-1)) = 15/36 = 5/12

The general direction of movement is away from the origin along a line with a slope of 5/12, about 22.6° CCW from the +x direction.

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The first attachment shows the derivative and its zeros and asymptotes. It also shows some of the detail of the parametric curve near the origin.

The second attachment shows the parametric curve over the domain for which it is defined, along with the point where t=3.

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3 years ago

How do I graph a solution set for the inequality 300+5x>550?

Alinara [238K]

First to solve the inequality
300 + 5x > 550
5x > 550 - 300
5x > 250
x > 50

Therefor the answers are all numbers bigger than 50

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3 years ago

Which of these statements is true for f(x)=(1/10)^x

lana66690 [7]

Step-by-step explanation:

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Analyzing option A)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

Putting $x = 1$ in the function

$f\left(1\right)=\:\left(\frac{1}{10}\right)^1$

$f\left(1\right)=\:\left\frac{1}{10}\right$

So, it is TRUE that when $x = 1$ then the out put will be $f\left(1\right)=\:\left\frac{1}{10}\right$

Therefore, the statement that '' The graph contains $\left(1,\:\frac{1}{10}\right)$ '' is TRUE.

Analyzing option B)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The range of the function is the set of values of the dependent variable for which a function is defined.

$\mathrm{The\:range\:of\:an\:exponential\:function\:of\:the\:form}\:c\cdot \:n^{ax+b}+k\:\mathrm{is}\:\:f\left(x\right)>k$

$k=0$

$f\left(x\right)>0$

Thus,

$\mathrm{Range\:of\:}\left(\frac{1}{10}\right)^x:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)>0\:\\ \:\mathrm{Interval\:Notation:}&\:\left(0,\:\infty \:\right)\end{bmatrix}$

Therefore, the statement that ''The range of $f(x)$ is $y > \frac{1}{10}$ " is FALSE

Analyzing option C)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

The domain of the function is the set of input values which the function is real and defined.

As the function has no undefined points nor domain constraints.

So, the domain is $-\infty \:$

Thus,

$\mathrm{Domain\:of\:}\:\left(\frac{1}{10}\right)^x\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:$

Therefore, the statement that ''The domain of $f(x)$ is $x>0$ '' is FALSE.

Analyzing option D)

Considering the function

$f\left(x\right)=\:\left(\frac{1}{10}\right)^x$

As the base of the exponential function is less then 1.

i.e. 0 < b < 1

Thus, the function is decreasing

Also check the graph of the function below, which shows that the function is decreasing.

Therefore, the statement '' It is always increasing '' is FALSE.

Keywords: function, exponential function, increasing function, decreasing function, domain, range

Learn more about exponential function from brainly.com/question/13657083

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4 years ago

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