We have a line tangent to the circle with center B at point C. We know that the angle formed between the tangent line at the point of intersection to the line extended from that point to the center of the circle is equal to 90°. In the problem, the 90° is for ∠BCA. We also know that the summation of all angles in a triangle is 180°. We have the solution below for the ∠BAC 180°=∠BAC + ∠BCA + ∠ABC 180°=∠BAC + 90° + 40° ∠BAC =50° The answer is 50°.
At its top floor, the Empire State Building stands <u>1,250 feet (380 meters)</u> tall. Counting the spire and antenna, the building clocks in at a mighty 1,454 feet (443 meters).
to get to -4 from 2 you have to subtract 6, making the slope x/6 but you said the slope is 3/2. divide 6 by 2 and you get 3. 3x3=9 making the slope 9/6. simplify and you get 3/2
