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sweet [91]
3 years ago
5

Please help with this right triangle problem

Mathematics
1 answer:
AveGali [126]3 years ago
3 0

Given:

The figure of a right angle triangle.

To find:

The measure of side AB.

Solution:

In a right angle triangle,

\cos \theta=\dfrac{Adjacent}{Hypotenuse}

In the given triangle,

\cos B=\dfrac{BC}{AB}

\cos (20^\circ)=\dfrac{7}{AB}

\cos (20^\circ)AB=7

AB=\dfrac{7}{\cos (20^\circ)}

On further simplification, we get

AB=\dfrac{7}{0.93969}

AB=7.449265

AB\approx 7.45

Therefore, the measure of AB is 7.45 units.

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<em><u>Solution:</u></em>

Given that we have to find the value of "m"

Given expression is:

m + 1\frac{3}{8} = 5

<em><u>Let us first convert the mixed fraction to improper fraction</u></em>

Steps to follow:

Divide the numerator by the denominator.

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1\frac{3}{8}=\frac{8 \times 1+3}{8} = \frac{8+3}{8} = \frac{11}{8}

Now the expression becomes,

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Keep the variable "m" on L.H.S and move the constant to R.H.S

m = 5 - \frac{11}{8}\\\\m = \frac{5 \times 8 -11}{8}\\\\m = \frac{40-11}{8}\\\\m = \frac{29}{8}\\\\\text{In mixed fractions, we can write as }\\\\m = \frac{29}{8} = 3\frac{5}{8}

Thus value of m is equal to 3.625 or \frac{29}{8} \text{ or } 3\frac{5}{8}

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Answer:

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