1.your going to look at the squares in the background , now on the bottom they are six squares with a line in the middle. your going to put a dot or line on the bottom line of the triangle on each squares ending point (like if your creating a ruler without the tiny lines)2. Ok now if you take the line in the middle( thats all ready in the triangle) you can say that makes to right angle triangle's ,so the one on the left and the one on the right now the one in the left has three squares ( cause remember you had 6 squares but the line in the middle of the triangle splits the triangle into 2 right angle triangles which makes it 3) your going to take each dot and bring it to the top or head of the triangle and you should be done
hoped it helped !!!
Answer:
y = 8x -25
Step-by-step explanation:
The two-point form of the equation of a line can be used.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (7-(-1))/(4-3)(x -3) +(-1)
y = 8(x -3) -1
y = 8x -25 . . . . slope-intercept form of the equation
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We don't know what you're starting with, so we don't know how to "complete the equation." Perhaps the above equation is sufficient for the task.
Answer:
21
Step-by-step explanation:
Answer:
3.5 m/s
Step-by-step explanation
Remove brackets
d = t^2 + 0.2t + 3.3t + .66
Combine
d = t^2 + 3.5t + .66
The initial velocity is 3.5
Answer:
- 4x² - 13x + 8 = 0
- 4x² - 11x + 5 = 0
- 16x² - 41x + 1 = 0
- x² + 5x + 4 = 0
- x² - 66x + 64 = 0
Step-by-step explanation:
<u>Given</u>
- α and β are roots of 4x²-5x-1=0
<u>Then the sum and product of the roots are:</u>
- α+b = -(-5)/4 = 5/4
- αβ = -1/4
(i) <u>Roots are α + 1 and β + 1, then we have:</u>
- (x - (α + 1))(x - (β + 1)) = 0
- (x - α - 1)(x - β - 1) = 0
- x² - (α+β+2)x + α+β+ αβ + 1 = 0
- x² - (5/4+2)x +5/4 - 1/4 + 1 = 0
- x² - 13/4x + 2= 0
- 4x² - 13x + 8 = 0
(ii) <u>Roots are 2 - α and 2 - β, then we have:</u>
- (x + α - 2)(x + β - 2) = 0
- x² + (a + β - 4)x - 2(α + β) + αβ + 4 = 0
- x² + (5/4 - 4)x - 2(5/4) - 1/4 + 4 = 0
- x² - 11/4x - 10/4 - 1/4 + 16/4 = 0
- x² - 11/4x + 5/4x = 0
- 4x² - 11x + 5 = 0
(iii) <u>Roots are α² and β², then:</u>
- (x - α²)(x-β²) = 0
- x² -(α²+β²)x + (αβ)² = 0
- x² - ((α+β)² - 2αβ)x + (-1/4)² = 0
- x² - ((5/4)² -2(-1/4))x + 1/16 = 0
- x² - ( 25/16 + 1/2)x + 1/16 = 0
- x² - 33/16x + 1/16 = 0
- 16x² - 33x + 1 = 0
(iv) <u>Roots are 1/α and 1/β, then:</u>
- (x - 1/α)(x - 1/β) = 0
- x² - (1/α+1/β)x + 1/αβ = 0
- x² - ((α+β)/αβ)x + 1/αβ = 0
- x² - (5/4)/(-1/4)x - 1/(-1/4) = 0
- x² + 5x + 4 = 0
(v) <u>Roots are 2/α² and 2/β², then:</u>
- (x - 2/α²)(x - 2/β²) = 0
- x² - (2/α² + 2/β²)x + 4/(αβ)² = 0
- x² - 2((α+β)² - 2αβ)/(αβ)²)x + 4/(αβ)² = 0
- x² - 2((5/4)² - 2(-1/4))/(-1/4)²x + 4/(-1/4)² = 0
- x² - 2(25/16 + 8/16)/(1/16)x + 4(16) = 0
- x² - 2(33)x + 64 = 0
- x² - 66x + 64 = 0