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aliya0001 [1]
3 years ago
7

Find all solutions for a triangle with a = 14, b= 12, and B = 90°.

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Answer:

No solution.

Step-by-step explanation:

Given

a = 14; b= 12; B = 90^\circ

Required

Find all possible solutions

If B = 90^\circ, then the triangle is right-angled and the hypotenuse is at b

Given that a = 14; b= 12;

This implies that a > b

In a right-angled triangle, the hypotenuse (side b) is the longest.

Since this is not true for the given sides, then the triangle has no solution.

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\frac{3}{5}÷2=\frac{3}{10}
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Video games sold: x
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Answer:

<u>The correct answer is D. 53x - 12</u>

Step-by-step explanation:

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6 0
3 years ago
49 + (-18) + (-23) = r (r=
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Answer:

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3 0
3 years ago
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One container is filled with mixture that is 25% acid. A second container is filled with a mixture that is 55% acid. The second
algol13

Answer:

Therefore the third container contains   \frac{735}{17}\% = 43.23 %  acid.

Step-by-step explanation:

Given that, One container is filled with the mixture that 25% acid. 55% acid is contain by second container.

Let the volume of first container be x cubic unit.

Since the volume of second container is 55% larger than the first.

Then the volume of the second container is

= (V\times \frac{100+55}{100})   cubic unit.

=\frac{155}{100}V  cubic unit.

The amount of acid in first container is

=V\times \frac{25}{100}  cubic unit.

=\frac{25}{100}V  cubic unit.

The amount of acid in second container is

=(\frac{155}{100}V \times \frac{55}{100}) cubic unit.

=\frac{8525}{10000}V cubic unit.

Total amount of acid =(\frac{25}{100}V+\frac{8525}{10000}V) cubic unit.

                                   =(\frac{2500+8525}{10000}V) cubic unit.

                                   =(\frac{11025}{10000}V)cubic unit.

Total volume of mixture =(V+\frac{155}{100}V) cubic unit.

                                       =\frac{100+155}{100}V cubic unit.

                                       =\frac{255}{100}V  cubic unit.

The amount of acid in the mixture is

=\frac{\textrm{The volume of acid}}{\textrm{The amount of mixture}}\times 100 \%

=\frac {\frac{11025}{10000}V}{\frac{255}{100}V}\times 100\%

=\frac{735}{17}\%

Therefore the third container contains  \frac{735}{17}\%  acid.

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3 years ago
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