Answer:
-16
Step-by-step explanation:
Given the sequence:
b(n)=b(n−1)−7, where b(1)=−2
b(2)=b(2−1)−7
=b(1)−7
=-2-7
b(2)=-9
Therefore, the 3rd term of the sequence
b(3)=b(3−1)−7
=b(2)-7 (Recall b(2)=-9 from above)
=-9-7
b(3)=-16
The 3rd term of the sequence is -16.
D is the right one, in all these suggestions , the number cube is rolled 1 time.
It so big problem
but you can do it
