Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
The y axis for dependent variables and x axis for independent
To solve for x just isolate x by moving the other variables so....:
First add c to both sides
g+c= y+x
Subtract y from both sides
g+c-y= x
That should be your final answer (we cannot come up with an actual digit for x because there are no numbers in this equation we simply can make an equation for x)
Answer:
Step-by-step explanation:
<u>Firstly we'll factorize the terms:</u>
45x³ = 3 * 3 * 5 * x * x * x
24x² = 2 * 2 * 2 * 3 * x * x
16x = 2 * 2 * 2 * 2 * x
<u>The factor which is common in all three terms is:</u>
= x
Hence GCF = x
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
