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Troyanec [42]
2 years ago
9

Solve for 8 - 6r + 3 = 5

Mathematics
1 answer:
Oksanka [162]2 years ago
5 0

Answer:

r = 1

Step-by-step explanation:

8 - 6r + 3 = 5

Combine like terms

11 - 6r = 5

Subtract 5 from both sides

6 - 6r = 0

Add 6r to both sides

6 = 6r

Divide both sides by 6

1 = r

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Round it to the nearest hundredth

Step-by-step explanation:

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The functions f(x)=√x^2+12x+36 and g(x)=x^3-12 are defined below. Which expression is equal to f(x) · g(x)? A.x^4-6x^3-12x+72 B.
Lostsunrise [7]

Answer:

C: x^4+6x^3-12x-72

Step-by-step explanation:

For the function : f(x)=√x^2+12x+36

It can be factorized to

f(x)=√(x+6)²

=x+6

f(x)*g(x)

=(x+6)(x^3-12)

Expand the brackets

=x^4-12x+6x^3-72

rearrange the numbers

x^4+6x^3-12x-72

3 0
2 years ago
Help!!! multiple choice!
Talja [164]
5.C

6.A

Hope this helps and is correct
4 0
3 years ago
URGENT! FAST REPLY PLS!
Sergeeva-Olga [200]

Answer:

Step-by-step example explanation:

DOMAIN:

{

x

∣

x

≠

3

2

}

RANGE:

{

y

∣

y

≠

3

2

}

Explanation:

The domain consists of all numbers you can legally plug into the original. The excluded "illegal" values would be dividing by zero or negatives under square roots.

This expression has a denominator, so there is a risk of illegally dividing by zero. This would happen only if

2

x

−

3

=

0

2

x

=

3

x

=

3

2

This means that

x

=

3

/

2

is excluded from the domain. Therefore,

Domain: All real numbers except

x

=

3

/

2

. More formally, you could state the domain as

{

x

∣

x

≠

3

2

}

.

For rational functions, you find the range by evaluating the degree of the numerator compared to the degree of the denominator. If the degree of the top > degree of bottoms, then you have a horizontal asymptote at

y

=

0

. If they are equal, you have a horizontal asymptote. The coefficient of highest degree in the numerator is divided by the coefficient of the highest degree on the bottom. The result is

y

=

that fraction. So in our case, you have a horizontal asymptote at

y

=

3

2

7 0
3 years ago
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