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emmainna [20.7K]
3 years ago
11

(This is for photography segment exam btw)

Computers and Technology
2 answers:
Mars2501 [29]3 years ago
5 0
C is correct for sureee
Alika [10]3 years ago
3 0

Answer:

C. Joseph Niepce

Explanation:

You might be interested in
In Python Calculate the BMI of a person using the formula BMI = ( Weight in Pounds / ( ( Height in inches ) x ( Height in inches
makvit [3.9K]

Answer:

weight_pounds=float(input("Enter the weight in pounds:\n"))#taking input of weight.

height_inches=float(input("Enter the height in inches:\n"))#taking input of thye height.

bmi=(weight_pounds/(height_inches**2))*703#calculating the bmi.

print('The body mass index is '+str(bmi))#printing the result.

Ouput:-

Enter the weight in pounds:

207.8

Enter the height in inches :

72

The body mass index is 28.163395061728398

Explanation:

The above written program is in python.First I have taken input from the user of the weight in pounds then taking input of the height in inches.Then calculating the bmi and storing it in the variable bmi.Then printing the bmi in the end.

6 0
3 years ago
In today's classrooms, computers are generally being used to
Vinvika [58]
The answer is enhance traditional instruction. Computers are often used by teachers so that the teachers may have an easier time with their visual aids. Now that we have tools like powerpoint presentations and excel files, it will be easier for the teachers to prepare 
4 0
3 years ago
Using Python I need to Prompt the user to enter in a numerical score for a Math Class. The numerical score should be between 0 a
yaroslaw [1]

Answer:

<em>The program doesn't use comments; See explanation section for detailed line by line explanation</em>

<em>Program starts here</em>

def lettergrade(subject,score):

     print(subject+": "+str(score))

     if score >= 90 and score <= 100:

           print("Letter Grade: A")

     elif score >= 80 and score <= 89:

           print("Letter Grade: B")

     elif score >= 70 and score <= 79:

           print("Letter Grade: C")

     elif score >= 60 and score <= 69:

           print("Letter Grade: D")

     elif score >= 0 and score <= 59:

           print("Letter Grade: F")

     else:

           print("Invalid Score")

maths = int(input("Maths Score: "))

english = int(input("English Score: "))

pe = int(input("PE Score: "))

science = int(input("Science Score: "))

arts = int(input("Arts Score: "))

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

Explanation:

The program makes the following assumptions:

Scores between 90–100 has letter grade A

Scores between 80–89 has letter grade B

Scores between 70–79 has letter grade C

Scores between 60–69 has letter grade D

Scores between 0–69 has letter grade E

<em>Line by Line explanation</em>

This line defines the lettergrade functions; with two parameters (One for subject or class and the other for the score)

def lettergrade(subject,score):

This line prints the the score obtained by the student in a class (e.g. Maths Class)

     print(subject+": "+str(score))

The italicized determines the letter grade using if conditional statement

<em>This checks if score is between 90 and 100 (inclusive); if yes, letter grade A is printed</em>

<em>      if score >= 90 and score <= 100:</em>

<em>            print("Letter Grade: A")</em>

<em />

<em>This checks if score is between 80 and 89 (inclusive); if yes, letter grade B is printed</em>

<em>      elif score >= 80 and score <= 89:</em>

<em>            print("Letter Grade: B")</em>

<em />

<em>This checks if score is between 70 and 79 (inclusive); if yes, letter grade C is printed</em>

<em>      elif score >= 70 and score <= 79:</em>

<em>            print("Letter Grade: C")</em>

<em />

<em>This checks if score is between 60 and 69 (inclusive); if yes, letter grade D is printed</em>

<em>      elif score >= 60 and score <= 69:</em>

<em>            print("Letter Grade: D")</em>

<em />

<em>This checks if score is between 0 and 59 (inclusive); if yes, letter grade F is printed</em>

<em>      elif score >= 0 and score <= 59:</em>

<em>            print("Letter Grade: F")</em>

<em />

<em>If input score is less than 0 or greater than 100, "Invalid Score" is printed</em>

<em>      else:</em>

<em>            print("Invalid Score")</em>

This line prompts the user for score in Maths class

maths = int(input("Maths Score: "))

This line prompts the user for score in English class

english = int(input("English Score: "))

This line prompts the user for score in PE class

pe = int(input("PE Score: "))

This line prompts the user for score in Science class

science = int(input("Science Score: "))

This line prompts the user for score in Arts class

arts = int(input("Arts Score: "))

The next five statements is used to call the letter grade function for each class

lettergrade("Maths Class: ",maths)

lettergrade("English Class: ",english)

lettergrade("PE Class: ",pe)

lettergrade("Science Class: ",science)

lettergrade("Arts Class: ",arts)

7 0
3 years ago
Write a C program that reads two hexadecimal values from the keyboard and then stores the two values into two variables of type
sattari [20]

Solution :

#include  $$

#include $$

#include $$

//Converts $\text{hex string}$ to binary string.

$\text{char}$ * hexadecimal$\text{To}$Binary(char* hexdec)

{

 

long $\text{int i}$ = 0;

char *string = $(\text{char}^ *) \ \text{malloc}$(sizeof(char) * 9);

while (hexdec[i]) {

//Simply assign binary string for each hex char.

switch (hexdec[i]) {

$\text{case '0'}:$

strcat(string, "0000");

break;

$\text{case '1'}:$

strcat(string, "0001");

break;

$\text{case '2'}:$

strcat(string, "0010");

break;

$\text{case '3'}:$

strcat(string, "0011");

break;

$\text{case '4'}:$

strcat(string, "0100");

break;

$\text{case '5'}:$

strcat(string, "0101");

break;

$\text{case '6'}:$

strcat(string, "0110");

break;

$\text{case '7'}:$

strcat(string, "0111");

break;

$\text{case '8'}:$

strcat(string, "1000");

break;

$\text{case '9'}:$

strcat(string, "1001");

break;

case 'A':

case 'a':

strcat(string, "1010");

break;

case 'B':

case 'b':

strcat(string, "1011");

break;

case 'C':

case 'c':

strcat(string, "1100");

break;

case 'D':

case 'd':

strcat(string, "1101");

break;

case 'E':

case 'e':

strcat(string, "1110");

break;

case 'F':

case 'f':

strcat(string, "1111");

break;

default:

printf("\nInvalid hexadecimal digit %c",

hexdec[i]);

string="-1" ;

}

i++;

}

return string;

}

 

int main()

{ //Take 2 strings

char *str1 =hexadecimalToBinary("FA") ;

char *str2 =hexadecimalToBinary("12") ;

//Input 2 numbers p and n.

int p,n;

scanf("%d",&p);

scanf("%d",&n);

//keep j as length of str2

int j=strlen(str2),i;

//Now replace n digits after p of str1

for(i=0;i<n;i++){

str1[p+i]=str2[j-1-i];

}

//Now, i have used c library strtol

long ans = strtol(str1, NULL, 2);

//print result.

printf("%lx",ans);

return 0;

}

4 0
3 years ago
Given two Strings String s1 = "11223351638791377189728193"; String s2 = "983763978669976862724569282405742578"; and String varia
inn [45]

Answer:

import java.math.BigInteger;  

public class Main {  

public static void main(String[] args)  {  

String s1 = "11223351638791377189728193";   String s2 = "983763978669976862724569282405742578";

BigInteger num1 = new BigInteger(s1);  

BigInteger num2 = new BigInteger(s2);  

BigInteger product = num1.multiply(num2);  

String s3 = product.toString(10);

System.out.println(s3);  

}  

}  

Explanation:

Because s1 and s2 contain large integers, the program need the biginteger module in other to compute the products of s1 and s2 when converted to integers.

This line initializes the two string variables s1 and s2

String s1 = "11223351638791377189728193";   String s2 = "983763978669976862724569282405742578";

The next two lines convert the two strings to BigInteger. This allows the program to multiply large integers

<em> BigInteger a = new BigInteger(s1);   </em>

<em>BigInteger b = new BigInteger(s2);  </em>

<em />

This computes the product of the two big integers

BigInteger product = num1.multiply(num2);  

This converts the product to String s3

String s3 = product.toString(10);

This prints s3

System.out.println(s3);  

}  

}  

7 0
3 years ago
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