Suppose that the functions s and t are defined for all real numbers x as follows.
1 answer:
Answer:
(s-t)(-1) = -1
(s+t)(-1) = -7
Step-by-step explanation:
Given the following set of functions
s(x)=2x-2
t(x)=3x
(s-t)(x) = s(t) - t(x)
(s-t)(x) = 2x - 2 - 3x
(s-t)(x) = -x -2
(s-t)(-1) = -(-1) - 2
(s-t)(-1) = 1-2
(s-t)(-1) = -1
(s+t)(x) = s(t) + t(x)
(s+t)(x) = 2x - 2 + 3x
(s+t)(x) = 5x -2
(s+t)(-1) = 5(-1) - 2
(s+t)(-1) = -5-2
(s+t)(-1) = -7
You might be interested in
Answer:
it would take 10 hours
Step-by-step explanation:
The coefficient in (2/3q-3/4) is 2/3 and in (-1/6q-r) is -1/6
160 percent of 19 = 30.4 hope this helps :)
The answer is 1/2.
I got this answer by multiplying all of them.
3^0 = 1
1/2 * 1 = 1/2
