Hello!
1.
find circumferece
c=2pir
c=2*6*pi=12pi
intercept is 5.4
2pi radians=all
part/whole=part/whole
5.4/12pi=x/2pi
times both sides by 12pi
5.4=6x
divide both sides by 6
0.9=x
answer is 0.9 radians
2.
assuming 9pi/5 radians
find circumference
c=2pir
c=2*26.9*pi
c=53.8pi
arc/circumference=(9pi/5)/2pi
x/(53.8pi)=(9pi/5)/(2pi)
x/(53.8pi)=18/5
times both sides by 53.8pi
x=608.46266 m
about x=608.46 m
Hope this Helps! Have A Wonderful Day! :)
A cross section is the shape we get when cutting straight through an object. The cross section of this object is a triangle. It is like a view into the inside of something made by cutting through it.
Answer:
Step-by-step explanation:
Researchers measured the data speeds for a particular smartphone carrier at 50 airports.
The highest speed measured was 76.6 Mbps.
n= 50
X[bar]= 17.95
S= 23.39
a. What is the difference between the carrier's highest data speed and the mean of all 50 data speeds?
If the highest speed is 76.6 and the sample mean is 17.95, the difference is 76.6-17.95= 58.65 Mbps
b. How many standard deviations is that [the difference found in part (a)]?
To know how many standard deviations is the max value apart from the sample mean, you have to divide the difference between those two values by the standard deviation
Dif/S= 58.65/23.39= 2.507 ≅ 2.51 Standard deviations
c. Convert the carrier's highest data speed to a z score.
The value is X= 76.6
Using the formula Z= (X - μ)/ δ= (76.6 - 17.95)/ 23.39= 2.51
d. If we consider data speeds that convert to z scores between minus−2 and 2 to be neither significantly low nor significantly high, is the carrier's highest data speed significant?
The Z value corresponding to the highest data speed is 2.51, considerin that is greater than 2 you can assume that it is significant.
I hope it helps!
Answer:
9 is the composite number.
Step-by-step explanation:
A composite number is a positive integer that can be formed by multiplying two smaller positive integers.
Answer:
Rs 2,500
Step-by-step explanation:
He has spent Rs1850 + Rs150 = Rs2000
if Rs2000 = 100%
X = 125%
By cross multiplication, we get;
100x = 2000 * 125
x = 250000/100
x = Rs 2,500
