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3 years ago

A function passes through the points (2,9) and (7,34). What are its rate of change and initial value?

Mathematics

1 answer:

Bess [88]3 years ago

5 0

Answer:

The rate of change: 1/5

Initial value: (0,-1)

Step-by-step explanation:

The rate of change is easily 5/25, we just have to simplify it to 1/5.

To get the intial value, just subtract (2,9) by the rate of change twice.

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If l=10, b=5, h=2, find the values of 2h(l+b)

Eddi Din [679]

Answer:

Step-by-step explanation:

given:

l = 10

b = 5

h = 2

to find:

2h(l + b)

substitute the given values of l , b and h

=2*2(10 + 5)

=4*15

=60

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Y_Kistochka [10]

Y intercept is where the line meets the Y axis
So the points shd be in (0,y) form.

So (0,0) (0,-7) (0,-0.25) are the y-intercepts in the following.

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Complete the equation, by supplying the missing exponent.

Vesna [10]

The answer is 1.927x102

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The value of 8y 2 –5y +1 when y= 1 is …………

ELEN [110]

Answer:

Step-by-step explanation:

8(1)^2 -5(1) +1

8(1) -5(1) +1

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3 years ago

Please please please help and solve this with steps, much help needed thank you :) 20 points for this!

leonid [27]

Answer:

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

$\frac{dy}{dx}y=x^3+2x-5x+3$

$\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}$

$\mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)$

1. $\mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:$

$y'\:y=x^3+2x-5x+3$

2. $\mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}$

$yy'\:=x^3-3x+3$

$N\left(y\right)\cdot y'\:=M\left(x\right)$

$N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3$

3. $\mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1$

4. $\mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}$

5. $\mathrm{Simplify}$

$y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}$

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3 years ago

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