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2 years ago

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Plane A leaves eastaboga traveling east at a speed twice that of plane be which is flying west. how fast is each plane traveling

if they fly for 3 hours and are 1800 miles apart?

1 answer:

ivanzaharov [21]2 years ago

5 0

Your doing great keep up the good work!!

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Find the common ratio of the geometric sequence 4, -20, 100, -500, ...

asambeis [7]

Answer:

r = -5. Find the pattern and write the recursive formula: a_n + 1 = - 5 a_nGiven the recursive formula: r =

6 0

1 year ago

Brainliest <br> Please do one of the above<br> (I would appreciate if you did more then one)

Temka [501]

Answer:

a) 52.5 ft. b)40.1ft c)12.5ft d) 72.6

Step-by-step explanation:

a) The height of the lighthouse is 84ft, and the angle of elevation is 58 degrees.

tan58=84/x

find x by dividing 84 by tan58, and you get 52.5ft.

b) do the same thing, except 131 is in the base of the right triangle shape. That being said, do tan17=x/131.

multiply 131 by tan17, and you get x=40.1 feet.

c) This question wants you to find the length of the slide, (basically the hypotenuse).

given the angle to be 46, do sin46=9/x

since sin is opp/hyp

9/sin46= 12.5ft

d) Find the angle of elevation by using inverse tan given the base to be 5, and the height to be 16ft.

tan^-1=(16/5)=theta

x=72.6 hope this helps!

5 0

2 years ago

Read 2 more answers

Answer the question math

Lerok [7]

Answer:

$7y-10$

Step-by-step explanation:

$9y-\frac{1}{2}\left(4y+20\right)$

To simplify this expression, first use the distributive property to distribute $\frac{1}{2}$ .

$9y-\frac{1}{2}(4y)+-\frac{1}{2}(20)$

Simplify.

$9y+-2y+-10$

Combine like terms, $9y$ and $-2y$ .

$7y-10$

The simplification of $9y-\frac{1}{2}(4y+20)$ is $7y-10$ .

I hope this helps ^^

Good luck

7 0

2 years ago

Dominik [7]

14+2x=62 (x=Pass cost)
-14 -14
(2x=48)/2
x=24

6.50+5.75+1.15x=18
12.25+1.15x=18
-12.25 -12.25
1.15x=5.75 divide both sides by 1.15
x=5

5 0

2 years ago

1) -24, -4, 16, 36, ...<br> Find a23

viktelen [127]

We're given the Arithmetic Progression <em>-24, -4, 16, 36 ...</em> .

We know that a term in an AP is generally represented as:

$\bf a_n\ =\ a\ +\ (n\ -\ 1)d$

where,

a = the first term in the sequence
n = the number of the term/number of terms
d = difference between two terms

We need to find $\sf a_2_3$ .

From the given progression, we have:

a = -24
n = 23
d = (-24 - (-4) = -20

Using these in the formula,

$\sf a_2_3\ =\ a\ +\ (n\ -\ 1)d\\\\\\a_2_3\ =\ -24\ +\ (23\ -\ 1)\ \times\ (-20)\\\\\\a_2_3\ =\ -24\ +\ 22\ \times (-20)\\\\\\a_2_3\ =\ -24\ -\ 440\\\\\\\bf a_2_3\ =\ -464$

Therefore, the 23rd term in the AP is -464.

Hope it helps. :)

7 0

2 years ago