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docker41 [41]
3 years ago
12

Plane A leaves eastaboga traveling east at a speed twice that of plane be which is flying west. how fast is each plane traveling

if they fly for 3 hours and are 1800 miles apart?
Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0
Your doing great keep up the good work!!
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Please help I'm horrible at fractions and I need to finish this...<br> Solve and simplify
Tpy6a [65]

Answer:

your answer would be 1/24

Step-by-step explanation:

this is because if you half it you get 5/120

then divide each by 5 to get 1/24

hope it helps!!

7 0
3 years ago
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Is it a function or not a function and if why is it either a function or not a function?
Butoxors [25]

Answer:

function

Step-by-step explanation:

8 0
3 years ago
A pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm, and 96 cm but does not resonate at any wave
erma4kov [3.2K]

Answer:

A Pipe that is 120 cm long resonates to produce sound of wavelengths 480 cm, 160 cm and 96 cm but does not resonate at any wavelengths longer than these. This pipe is:

A. closed at both ends

B. open at one end and closed at one end

C. open at both ends.

D. we cannot tell because we do not know the frequency of the sound.

The right choice is:

B. open at one end and closed at one end .

Step-by-step explanation:

Given:

Length of the pipe, L = 120 cm

Its wavelength \lambda_1 = 480 cm

                         \lambda_2 = 160 cm and \lambda_3 = 96 cm

We have to find whether the pipe is open,closed or open-closed or none.

Note:

  • The fundamental wavelength of a pipe which is open at both ends is 2L.
  • The fundamental wavelength of a pipe which is closed at one end and open at another end is 4L.

So,

The fundamental wavelength:

⇒ 4L=4(120)=480\ cm

It seems that the pipe is open at one end and closed at one end.

Now lets check with the subsequent wavelengths.

For one side open and one side closed pipe:

An odd-integer number of quarter wavelength have to fit into the tube of length L.

⇒  \lambda_2=\frac{4L}{3}                                   ⇒  \lambda_3=\frac{4L}{5}

⇒ \lambda_2=\frac{4(120)}{3}                              ⇒  \lambda_3=\frac{4(120)}{5}

⇒ \lambda_2=\frac{480}{3}                                  ⇒  \lambda_3=\frac{480}{5}

⇒ \lambda_2=160\ cm                           ⇒   \lambda_3=96\ cm  

So the pipe is open at one end and closed at one end .

6 0
3 years ago
The lenght of a rectangle is 4 cm less than three times the width. the perimeter is 64 cm
dybincka [34]
Let the width be x cm.
Then length=3x-4 cm.
Its perimeter is 64 cm.
We know that perimeter of a rectangle= 2(length+width)
So,
2(3x-4+x)=64
6x-8+2x=64
6x+2x=64+8
8x=72
x=9
Therefore,
length=(3×9-4)cm=(27-4)cm=23 cm.
Width=9 cm.
5 0
2 years ago
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What is the approximate volume of a cylinder with a height of 2 ft and a radius of 6 ft? Use 3.14 to approximate pi. Express you
marissa [1.9K]
The volume of a cylinder is Pi times the radius^2 times the height

Volume = Pi x 6^2 x 2
Volume = 226.2
6 0
3 years ago
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