N^3 +4n^2 +8n -16
hope it help
mark me brainliest if i right ty
The probability of “landing” in the shaded region to the nearest hundredth is equal to 0.79 or 79.0%.
<h3>How to determine the
probability?</h3>
First of all, we would determine the area of the given geometric shapes.
For the square, we have:
Mathematically, the area of a square can be calculated by using this formula;
Area = x²
Area = 50²
Area = 2500 ft².
For the circle, we have:
Mathematically, the area of a circle can be calculated by using this formula;
Area = πd²/4
Area = (3.142 × 50²)/4
Area = 1,963.75 ft².
Now, we can determine the probability as follows:
Probability = 1963.75/2500
Probability = 0.79 or 79.0%.
<h3>When the side length is 40 ft.</h3>
Area = x²
Area = 40²
Area = 1600 ft².
For the circle, we have:
Area = πd²/4
Area = (3.142 × 40²)/4
Area = 1256.8 ft².
Probability = 1256.8/1600
Probability = 0.79 or 79.0%.
Read more on probability here: brainly.com/question/24441555
#SPJ1
We will start with our guess of 12, since 12*2 = 24.
Divide 24 by 12; 24/12=2. Average this answer with our guess: (12+2)/2=7. This is our new guess.
24/7=3.428571429. Average this with our guess of 7: (3.428571429+7)/2=5.214285715. This is our new guess.
24/5.214285715=4.602739726. Averaging with our guess: (4.602739726+5.214285715)/2=4.90851272. New guess!
24/4.90851272=4.889464766. Averaging with our guess: (4.889464766+4.90851272)/2=4.898988743. New guess! You can see as we go through our guesses are closer and closer to the same number...)
24/4.898988743=4.898970228. Averaging: (4.898970228+4.898988743)/2=4.898979486. At this point our answer is the same every time down to the hundred-thousandth. Our estimate to the nearest hundredth would be 4.90.
Answer:
4.93333...
Step-by-step explanation:
-24 + (-10) + (-40) = -74
-5 * 3 = -15
-74 /-15 = 4.93333...
Answer:
Yes
Step-by-step explanation:
"data includes which problems where attempted, the time at which each problem was attempted, the answers the student submitted and whether they were correct, the duration the student was working on each problem, whether each assignment was completed on time and the completion percentage for each assignment" (paragraph 4).
Its on their privacy policy