3 years ago

2x+3y=6 3x-y=2 How many solutions does this have, one, none or infinite

Mathematics

2 answers:

sergey [27]3 years ago

6 0

Y=-2/3x + 2
y=3x-2

one because the slopes are different

alexandr1967 [171]3 years ago

4 0

A) 2x+3y=6
B) 3x-y=2
Multiplying equation B by 3
9x -3y = 6 then adding it to equation A
2x + 3y = 6
11x = 12
x = 12 / 11

2x + 3y = 6
3y = 6 -2x
y = 2 -(2/3)x
y = 2 -(2/3) * (12/11)
y = 2 -8/11
y = 14 / 11

Therefore, it has one solution

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valkas [14]

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3 years ago

What is the value of x after these statements if the starting value of x is 3.

kolbaska11 [484]

[A]
$3^{2}=9$
$5^{3}=125$
$9\neq25$

Ignore

[B]
$3^{2} = 9$
$9 \ \textgreater \ 3$
Yes

$3^{3}=27$
$4( 3^{2})=36

27 \ \textless \ 36$
Yes

Therefore
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[C]
$4^{5}=1024

 5^{4}=625

1024\ \textless \ 625$
No

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 5^{5}=3125

3125\ \textgreater \ 3125$
No

Ignore

[D]
$5^{5}=3125

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3125\ \textgreater \ 32$
Yes

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25\ \textless \ 11$
No

Therefore
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[E]
$8\ \textgreater \ 7$
Yes

Therefore
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4 0

3 years ago