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Andreyy89
4 years ago
10

2x+3y=6 3x-y=2 How many solutions does this have, one, none or infinite

Mathematics
2 answers:
sergey [27]4 years ago
6 0
Y=-2/3x + 2
y=3x-2

one because the slopes are different

alexandr1967 [171]4 years ago
4 0
<span>A) 2x+3y=6
B) 3x-y=2
Multiplying equation B by 3
9x -3y = 6 then adding it to equation A
2x + 3y = 6
11x = 12
x = 12 / 11
</span>
2x + 3y = 6
3y = 6 -2x
y = 2 -(2/3)x
y = 2 -(2/3) * (12/11)
y = 2 -8/11
y = 14 / 11

Therefore, it has one solution


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On a coordinate plane, 2 lines are shown. Line H J has points (negative 4, negative 2) and (0, 4). Line F G has points (negative
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Answer:

They are not perpendicular because their slopes are not negative reciprocals.

Step-by-step explanation:

Well first we need to find slope.

\frac{y^2-y^1}{x^2-x^1}

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(-4,-2) , (0,4)

y2 is 4 y1 is -2, so 4 - -2 = 6

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Hence, y = 3/2x + 4 is the slope of line HJ

Line FG)

(-4,1) , (0,-2)

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Because (0,-2) is missing an x value -2 is the y intercept,

Equation: y = -3/4x - 2

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