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mr Goodwill [35]
3 years ago
7

The zeros of function dare -3 and 8. Which expression could be a factor of function d?

Mathematics
1 answer:
erastovalidia [21]3 years ago
3 0

Answer:

(x + 3)

Step-by-step explanation:

Using the zero product property

x-a = 0  x-b = 0  where a and b are the zeros

(x-a)(x-b) =0

(x- -3)(x -8) =0

(x+3) (x-8) =0

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Simplify the expression below. Then classify the resulting expression
evablogger [386]

Answer:

Simplified = 5

Classification = Monomial

Step-by-step explanation:

<h2>PART I: Simplify the expression</h2>

<u>Given expression:</u>

 3x² + 6x + 5 - 3x (2 + x)

<u>Expand parenthesis by distributive property:</u>

= 3x² + 6x + 5 - 3x (2) - 3x (x)

= 3x² +6x + 5 - 6x - 3x²

<u>Put like terms together:</u>

= 3x² - 3x² + 6x - 6x + 5

= 0 + 0 + 5

= \boxed{5}

<h2>PART II: Classify polynomial</h2>

<u>Concept:</u>

Polynomial is classified by the number of terms a polynomial has.

  • Monomial: a polynomial with only one term
  • Binomial: a polynomial with two terms
  • ...

<u>Classify the given expression:</u>

Original = 3x² + 6x + 5 - 3x (2 + x)

Simplified = 5

5 is a constant and it has only one term

Therefore, it is a <u>monomial</u>.

Hope this helps!! :)

Please let me know if you have any questions

3 0
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