The zeros of function dare -3 and 8. Which expression could be a factor of function d?

Mathematics

1 answer:

erastovalidia [21]3 years ago

3 0

Answer:

(x + 3)

Step-by-step explanation:

Using the zero product property

x-a = 0 x-b = 0 where a and b are the zeros

(x-a)(x-b) =0

(x- -3)(x -8) =0

(x+3) (x-8) =0

You might be interested in

Math question:<br> Solve for x<br> 2/3(x - 7) = -2

sasho [114]

2(x-7)/3=-2
3*2(x-7)/2*3=-2*3/2
x-7=-2*3/2
x-7=3*-1
x+(7-7)-7-3
x=7-3
x=4

3 0

3 years ago

Worth 30 points please give the whole answers.

k0ka [10]

1. (2r + 9)(2r-9) = 4r^2 -81
+ (2r - 9)^2 = 4r^2 - 36r + 81
= 8r^2 - 36r

2. 12 - 5 [ a^2 + a - 1 ] + 5a
= 12 - 5a^2 - 5a + 5 +5a
= 17 - 5a^2

x^3 + 3x^2 + 6x + 18
______
3. x-3/ x^4 + 7
- ( x^4 - 3x^3)
----------------
3x^3 + 7
- (3x^3 - 6x^2)
-------------------
6x^2 + 7
- (6x^2 - 18x)
-------------------
18x + 7
- (18x - 54)
--------------
7 + 54 = R = 61

welp That's What I get

5 0

3 years ago

Read 2 more answers

13. If 6 times the 6th term of an A.P. is equal to

romanna [79]

Answer:

see explanation

Step-by-step explanation:

The n th term of an AP is

$a_{n}$ = a₁ + (n - 1)d