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garri49 [273]
2 years ago
15

For every lion there are 7 giraffes

Mathematics
2 answers:
dimaraw [331]2 years ago
7 0

Answer:

.................

Step-by-step explanation:

hmmm

?

marin [14]2 years ago
7 0

Answer:

7 times however many lions they have

Step-by-step explanation:

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The functions f(x) and g(x) in the graph below are most likely which two equations?
gtnhenbr [62]

Answer:

It's C.

Step-by-step explanation:

The red curve  pass through the point (0, 1) and also y = 2 when x = 1 ,  so this is y = 2^x. The inverse is the reflection of  f(x) in x = y so the blue curve is y = log2 x.

6 0
3 years ago
A farmer wants to fence an area of 13.5 million square feet in a rectangular field and then divide it in half with a fence paral
denis23 [38]

Answer:

  F = 3x +(2.7×10^7)/x

Step-by-step explanation:

The formulas for area and perimeter of a rectangle can be used to find the desired function.

<h3>Area</h3>

The area of the rectangle will be the product of its dimensions:

  A = LW

Using the given values, we have ...

  13.5×10^6 = xy

Solving for y gives ...

  y = (13.5×10^6)/x

<h3>Perimeter</h3>

The perimeter of the rectangle is the sum of the side lengths:

  P = 2(L+W) = 2(x+y)

<h3>Fence length</h3>

The total amount of fence required is the perimeter plus one more section that is x feet long.

  F = 2(x +y) +x = 3x +2y

Substituting for y, we have a function of x:

  F = 3x +(2.7×10^7)/x

__

<em>Additional comment</em>

The length of fence required is minimized for x=3000. The overall size of that fenced area is x=3000 ft by y=4500 ft. Each half is 3000 ft by 2250 ft. Half of the total 18000 ft of fence is used for each of the perpendicular directions: 3x=2y=9000 ft.

4 0
2 years ago
Help me with differentation and integration please!!
Marina86 [1]

Answer:

See below

Step-by-step explanation:

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

Recall

\dfrac{d}{dx}\tan x=\sec^2

Using the chain rule

\dfrac{dy}{dx}= \dfrac{dy}{du} \dfrac{du}{dx}

such that u = \tan x

we can get a general formulation for

y = \tan^n x

Considering the power rule

\boxed{\dfrac{d}{dx} x^n = nx^{n-1}}

we have

\dfrac{dy}{dx} =n u^{n-1} \sec^2 x \implies \dfrac{dy}{dx} =n \tan^{n-1} \sec^2 x

therefore,

\dfrac{d}{dx}\tan^3 x=3\tan^2x \sec^2x

Now, once

\sec^2 x - 1= \tan^2x

we have

3\tan^2x \sec^2x =  3(\sec^2 x - 1) \sec^2x = 3\sec^4x-3\sec^2x

Hence, we showed

\dfrac{d}{dx} (\tan^3 x) = 3\sec^4 x - 3\sec^2 x

================================================

For the integration,

$\int \sec^4 x\, dx $

considering the previous part, we will use the identity

\boxed{\sec^2 x - 1= \tan^2x}

thus

$\int\sec^4x\,dx=\int \sec^2 x(\tan^2x+1)\,dx = \int \sec^2 x \tan^2x+\sec^2 x\,dx$

and

$\int \sec^2 x \tan^2x+\sec^2 x\,dx = \int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx $

Considering u = \tan x

and then du=\sec^2x\ dx

we have

$\int u^2 \, du = \dfrac{u^3}{3}+C$

Therefore,

$\int \sec^2 x \tan^2x\,dx + \int \sec^2 x\,dx = \dfrac{\tan^3 x}{3}+\tan x + C$

$\boxed{\int \sec^4 x\, dx  = \dfrac{\tan^3 x}{3}+\tan x + C }$

6 0
2 years ago
Mary rounds these numbers to the nearest hundred. Which number does she round to 400? Choose all that apply. A) 351. B) 369 C).
natulia [17]

Answer:

401

Step-by-step explanation:

7 0
2 years ago
The lifetime of a machine part has a continuous distribution on the interval​ (0, 50​) with probability density function​ f, whe
Strike441 [17]

Answer:

Probability that the lifetime of the machine part is less than 13 = 0.6782

Step-by-step explanation:

given that f(x)=(10+x)^{-2}

Normalizing the function we get

\int_{0 }^{50}cf(x)dx=1

\int_{0 }^{50}c(10+x)^{-2}dx=1

\therefore a=\frac{1}{\int_{0 }^{50}(10+x)^{-2}dx}

\therefore a=12

P(x< 13)=\int_{0}^{13}12(10+x)^{-2}dx\\\\P(X< 13)=0.6782

4 0
3 years ago
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