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Given :
A particle moves in the xy plane starting from time = 0 second and position (1m, 2m) with a velocity of v=2i-4tj .
To Find :
A. The vector position of the particle at any time t .
B. The acceleration of the particle at any time t .
Solution :
A )
Position of vector v is given by :
B )
Acceleration a is given by :
Hence , this is the required solution .
We are given
The order of the letter sequence is important. The letters pair up based on how they are arranged. We see that A and E are the first letters of the sequences. So this means that angles A and E are the same measure
angle A = angle E
3x+20 = 5x-80
3x-5x = -80-20
-2x = -100
x = -100/(-2)
x = 50
Use this x value to find the measure of angle A
angle A = 3x+20
angle A = 3(50)+20
angle A = 150+20
angle A = 170 degrees
<h3>Therefore, the statement "the measure of angle A is 45 degrees" is <u>false</u>.</h3>