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3 years ago

Please I need help on this

Mathematics

2 answers:

svetoff [14.1K]3 years ago

5 0

56 + 41 + x = 180
97 + x = 180
x = 180 - 97
x = 83 degrees

otez555 [7]3 years ago

3 0

It is 83 degrees because the 56 is equivalent to the one across from it so 41 plus 56 is 97 and 180 minus 97 is 83 which is the answer.

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An integer is chosen at random from 1 to 50 inclusive. Find the probability that the chosen integer is divisible by 3. A- 3/50 B

11111nata11111 [884]

First, we need to know how many things between 1 and 50 are divisible by 3, this would be 16. Then we would divide this by the total number of integers, 16/50=8/25. This means your answer is C.

4 0

3 years ago

Read 2 more answers

Daisy is going 12 mph and Sally is going 8 mph if they where 60 miles apart how many hours would it take for them to meet up

abruzzese [7]

Answer:

3 hours

Step-by-step explanation:

we know that

The speed is equal to divide the distance by the time

Let

s ----> the speed in mph

d -----> the distance in miles

t ----> the time in hours

x ----> distance traveled by Daisy to the meeting point

60-x ----> distance traveled by Sally to the meeting point

$s=\frac{d}{t}$

Solve for d

$d=st$

Distance traveled by Daisy to the meeting point

$d=st$

we have

$d=x\ mi\\s=12\ mph$

substitute

$x=12t$ ----> equation A

Distance traveled by Sally to the meeting point

$d=st$

we have

$d=(60-x)\ mi\\s=8\ mph$

substitute

$60-x=8t$ ----> equation B

substitute equation A in equation B

$60-12t=8t$

solve for t

$12t+8t=60\\20t=60\\t=3\ hours$

7 0

3 years ago

Please help if you know the answer thank you

AfilCa [17]

Answer:

The answer you picked is the correct one.

Step-by-step explanation:

All imma say is good job, your smart.

4 0

3 years ago

Simplify: √(1+x) /√(1+x) - √(1 -x) - 1-x /√(1 -x) + x -1

soldier1979 [14.2K]

Step-by-step explanation:

Given that: [√(1+x)/{√(1+x) - √(1-x)}] - [(1-x)/{√(1-x²) + x -1}]

Here, we see that in first fraction the denominator is √(1+x)-√(1-x) , as we know that the rational factor √(a+b)-√(a-b) is √(a+b)+(a-b). Therefore, the rationalising factor of √(1+x)-√(1-x) is √(1+x)+√(1-x). On rationalising the denominator them.

= [√(1+x)/{√(1+x)-√(1-x)}] * [{√(1+x)+√(1-x)}/{√(1+x)+√(1-x)}] - [(1-x)/{√(1-x²) + x -1}]

= [{√(1+x)(√(1+x)+√(1-x)}/{√(1+x)-√(1-x) - √(1+x)+√(1-x)}] - [(1-x)/{√(1-x²) + x -1}]

Now, comparing the first fraction denominator with (a-b)(a+b), we get

a = √(1+x)
b = √(1-x)
a = √(1+x)
b = √(1-x)

Using identity (a-b)(a+b) = a² - b², we get

= [{√(1+x)(√(1+x)+√(1-x)}/{√(1+x)² - √(1-x)²}] - [(1-x)/{√(1-x²) + x -1}]

= [{√(1+x)(√(1+x)+√(1-x)}/{(1+x) - (1-x)}] - [(1-x)/{√(1-x²) + x -1}]

Now, multiply the numerator on both brackets.

= [{√(1+x) * √(1+x) + √(1+x) * √(1-x)}/{(1+x) - (1-x)}] - [(1-x)/{√(1-x²) + x -1}]

Comparing the first fraction numerator with (a+b)(a+b) , we get

a = √1
b = √x

Using identity (a+b)(a+b) = (a+b)², we get

= [{√(1+x)²+ √(1+x) * √((1+x)(1-x))}/{(1+x) - (1-x)}] - [(1-x)/{√(1-x²) + x -1}]

Cancel out the first fraction denominator numbers 1 and -1 to get 0.

= [{(1+x)+√(1-x²)}/(x+x+0)] - [(1-x)/{√(1-x²) + x -1}]

= [{(1+x)+√(1-x²)}/(x+x)] - [(1-x)/{√(1-x²) + x -1}]

= [{(1+x)+√(1-x²)}/2x] - [(1-x)/{√(1-x²) + x -1}]

= [{1+x+√(1-x²)}{√(1-x²)x-1}-{(1-x)(2x)}]/[2x{√(1-x²)+x-1}]

= [√(1-x²) + x-1 + x√(1-x²) + x² - x + {√(1-x²)}² + x√(1-x²)-√(1-x²) - 2x + 2x²]/[2x{√(1-x²)+x-1}]

= {(√(1-x²) 2x -1 + 3x² + 2x√(1-x²) + 1-x² - √(1-x²)}/[2x{√(1-x²)+x-1}]

Cancel out √(1-x) and -√(1-x) in numerator.

= {-2x - 1 + 2x√(1-x²) + 3x² + 1 - x²}/[2x{√(1-x²)}+x-1}]

Cancel out -1 and 1 in numerator to get 0.

= [2x√(1-x²) - 2x + 2x²}/[2x{√(1-x²)+x-1}]

= {2x{√(1-x²)} + x - 1}]/[2x{√(1-x²)}+x-1}

= 1

Answer: Hence, the simplified form of the expression [√(1+x)/{√(1+x) - √(1-x)}] - [(1-x)/{√(1-x²) + x -1}] is 1.

Please let me know if you have any other questions.

6 0

3 years ago

Chloe breaks into the pantry after Albert goes to work. She finds and opens a family-pack of mixed nuts. After surfing the web,

Firdavs [7]

Solution :

In this case we have to use $\text{chi square test}$ for the goodness of fit.

Null hypothesis is : $H_0 :$ Data follows the given distribution

Alternate hypothesis is : $H_a:$ Data do not follow the given distribution

The level of significance, $\alpha = 0.05$

The test statistics is given by :

Chi square = $\sum\frac{(O-E)^2}{E}$

Here O is the observed frequencies

E is the expected frequencies

So we have, N = number of the categories = 4

df = degrees o freedom = N - 1

= 4 - 1 = 3

Critical value = $7.814727764$

Calculating the table for the test statistics are given as :

Category prop. O E $\frac{(O-E)^2}{E}$

A 0.2 14 20 1.80

C 0.3 28 30 0.13

M 0.1 6 10 1.60

P 0.4 52 40 3.60

Total 1 100 100 7.13

The test statics = chi square = $\sum\frac{(O-E)^2}{E}$ = 7.13

$X^2$ statistics = 7.13

P-value = 0.067767248

P -value > $\alpha = 0.05$

Therefore, we do not reject the $\text{null hypothesis}$ . There is sufficient evidence to conclude that the data follows the given distribution. So there is sufficient evidence to conclude the given claim is true.

4 0

3 years ago