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2 years ago

ASAP HELP!! PLEASEEEE!!

Mathematics

1 answer:

Ne4ueva [31]2 years ago

8 0

Answer:

Step-by-step explanation:

5.1, please this is just a guess from using my head to calculate

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HURRY FIRST GETS BRAINLLEST The diagram below shows a circular pizza with a diameter of 14 inches. The pizza is in a square box

boyakko [2]

Answer:

pls do mark my answer as the brainliest..........

Step-by-step explanation

portion of square empty = 256 - 153.86 = 102.14cm^2

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2 years ago

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Anna35 [415]

Answer:

Step-by-step explanation:

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2 years ago

Find the area of the circle. Use 3.14 for Pi

IceJOKER [234]

Answer:

113.04 cm squared

Step-by-step explanation:

the area of a circle is:

A=πr2

so as you written before the pi must be 3.14

and the radius is the diameter/2(12/2=6)

A= 3.14 x 6 x 6

A= 113.04 cm squared

3 0

2 years ago

Read 2 more answers

Solve for x and y.<br><br> 4x-3y=16<br> -2x+4y=-2<br><br> DUE 2/7/17!

Trava [24]

$\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.$

<span>Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
</span> $\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.$
$\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.$
--------------------
$5y = 12$
$\boxed{\boxed{y = \frac{12}{5}}}\end{array}}\qquad\quad\checkmark$

Let's replace the value found in the first equation:
$4x-3y=16\:(I)$
$4x-3*( \frac{12}{5}) =16$
$4x - \frac{36}{5} = 16$
least common multiple (5)
$\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}$
$20x - 36 = 80$
$20x = 80 + 36$
$20x = 116$
$x = \frac{116}{20} \frac{\div4}{\div4} \to\: \boxed{\boxed{x = \frac{29}{5} }}\end{array}}\qquad\quad\checkmark$

4 0

3 years ago

What is the period of the function y = 2sin x?. A. 2Pi. B. Pi. C. [-2,2]. D. All Real Numbers

Morgarella [4.7K]

Answer:

Step-by-step explanation:

The given function is

$y=2sin(x)$

Notice that the indepedent variable doesn't have any transformation, that means the period doesn't change. In other words, this function has the same period than its parent function which is $2\pi$ .

Therefore, the answer is A.

The image attached shows the graph of this function, there you can observe the period of the function.

Also, notice that this function is verticall stretched by a scale of 2, which doesn't change its original period.

8 0

2 years ago