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tekilochka [14]
3 years ago
14

Nm i figured it out and i cant delete the question for some reason

History
1 answer:
ANTONII [103]3 years ago
3 0

Answer:

i know you got it already but can i get brainliest

Explanation:

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Read 2 more answers
An hourly wage is normally distributed with a mean of $6.75 and a standard deviation of $0.55. What is the probability that an e
monitta

Answer:

Option A. 81.5%

Explanation:

Population mean, \mu = 6.75

Standard deviation, \sigma = 0.55

The question is to find p(5.65 < \bar{x} < 7.30)

The z value is given by the formula:

z = \frac{\bar{x} - \mu}{\sigma}

z - value corresponding to the mean, \bar{x} = 5.65:

z_1 = \frac{5.65 - 6.75}{0.55}\\z_1 =-2.0

z - value corresponding to the mean, \bar{x} = 7.30:

z_1 = \frac{7.30 - 6.75}{0.55}\\z_1 =1.0

p(5.65\leq  \bar{x} \leq 7.30) = p(-2.0 \leq  z \leq  1.0)\\p(-2.0 \leq  z \leq  1.0) = p(z\leq 1) - p(z\leq -2)\\ p(-2.0 \leq  z \leq  1.0) = 0.84134 - 0.02275\\p(-2.0 \leq  z \leq  1.0) = 0.81859 \\p(-2.0 \leq  z \leq  1.0) = 0.82

Probability that an employee’s hourly wage is between $5.65 and $7.30 = 81.5%

4 0
3 years ago
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