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lesantik [10]
3 years ago
13

THIS IS TIMED!!

Mathematics
2 answers:
nlexa [21]3 years ago
7 0

Answer:

A,C,E

Step-by-step explanation:

i just answered it on edg

wel3 years ago
4 0

Answer:

a c e

Step-by-step explanation:

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Make the eqaution equal 4,416 for alot of points
irga5000 [103]

Answer:

2 *( 3+7-9) =(1+5) - ( 8 -4 )

Step-by-step explanation:

2 _( 3_7_9) = (1_ 5) _ ( 8 _4 )

I just started playing with things

2 *( 3+7-9) = (1_5 ) _ ( 8 _4 )

2 * (10-9)

2*1

So the left side is 2

Now to make the right side 2

(1+5) - ( 8 -4 )

6 - 4

2

4 0
3 years ago
Read 2 more answers
Multiply (2x+1)(6x^2+8+9)
spayn [35]

Answer:

12x3+6x2+34x+17

Step-by-step explanation:

(2x+1)(6x2+8+9)

=(2x+1)(6x2+8+9)

=(2x)(6x2)+(2x)(8)+(2x)(9)+(1)(6x2)+(1)(8)+(1)(9)

=12x3+16x+18x+6x2+8+9

=12x3+6x2+34x+17

6 0
3 years ago
What is the equation has intercepts at x(1, 0, 0), y(0, -1,0), and z(0, 0, 2)
bulgar [2K]

In intercept form, the plane that has these intercepts is ...

... x/(x-intercept) + y/(y-intercept) + z/(z-intercept) = 1

... x/1 + y/(-1) + z/2 = 1

... 2x -2y +z = 2 . . . . . in standard form

3 0
4 years ago
Please answer this correctly please label the numbers correctly
Ierofanga [76]

Answer:

Step-by-step explanation:

All u need to do is graph the points so for -4,5 go 4 left then go  up

8 0
3 years ago
Find the solution of the given initial value problem. ty' + 6y = t2 − t + 1, y(1) = 1 6 , t > 0
gtnhenbr [62]

Answer:

Step-by-step explanation:

Given is a differential equation as

ty' + 6y = t^2 - t + 1, y(1) = 1 6 , t > 0

Divide this by t to get in linear form

y'+6y/t = t-1+1/t

This is of the form

y' +p(t) y = Q(t)

where p(t) = 1/te^(\int 1/tdt) = t

So solution would be

yt = \int t^2-t+1 dt\\= t^3/3-t^2/2+t+C

siubstitute y(1) = 16

16 = 16^3/3-128+1+C\\C = -1206

4 0
3 years ago
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