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tiny-mole [99]
3 years ago
5

To add integers with the same sign

Mathematics
2 answers:
Mariana [72]3 years ago
5 0

Arithmetic

-3-2=5

because

-3-2

=

-3 + -2

3 negatives + 2 negatives = 5 negatives

taurus [48]3 years ago
4 0
-3-2 pretty sure that’s the answer
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valentina_108 [34]
A=162sq......... bless up
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INEQUALITIES-PLEASE HELP! Tricia receives a $5 allowance every week. She also earns $6.50 for every hour that she baby-sits. Nex
Zinaida [17]

Answer:

6.50x + 5 = 21.25 is the answer

Step-by-step explanation:

x=2.5

4 0
4 years ago
Live Fund are selling their holding at $5,000 per share.How much would Live Fund receive it they sold half thier holding in Mark
zhannawk [14.2K]

Live Fund receive \bold{\$2500 A} it they sold half thier holding in Marks Brothers.

<u>Solution:</u>

Given: Sale price of Live Fund holding = 5000 dollar

To find: Amount that Live Fund will get if they sell half of their holding in Marks Brothers.

Assume the total number of shares held by Live Fund in Marks Brothers as A

Therfore, half the holdings (or half the number of shares) of Live Fund will be \frac{A}{2}.

Thus, if each share is valued at \$5000, then the total value of the number of shares sold will be as follows,

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5 0
4 years ago
For any circle, which ratio is equal to the number n? Select all that apply. Plsss help me!!
barxatty [35]

Answer:

Options A-C-F

Step-by-step explanation:

we know that

<em>The circumference of a circle is equal to</em>

C=\pi D  or  C=2\pi r

where

D is the diameter and r is the radius

therefore

\pi =\frac{C}{D}  or \pi =\frac{C}{2r}

The number pi is the ratio circumference - diameter or is the ratio circumference - 2 times radius

<em>The area of the circle is equal to</em>

A=\pi r^{2}

therefore

The number pi is the ratio Area - radius squared

6 0
3 years ago
I don't know if this is right... please someone help mee
worty [1.4K]
For the first circle, let's use the pythagorean theorem

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{8^2+15^2}\implies c=\sqrt{289}\implies c=17

now, it just so happen that the hypotenuse on that triangle, is actually 17, but we used the pythagorean theorem to find it, and the pythagorean theorem only works for right-triangles.

 so if the hypotenuse is actually 17, that means that triangle there is actually a right-triangle, meaning that the radius there, and the outside line there, are both meeting at a right-angle.

when an outside line touches the radius line, and they form a right-angle, the outside line is indeed a tangent line, since the point of tangency is always a right-angle with the radius.



now, let's check for second circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{11^2+14^2}\implies c=\sqrt{317}\implies c\approx 17.8044938

well, low and behold, we didn't get our hypotenuse as 16 after all, meaning, that triangle is NOT a right-triangle, and that outside line is not touching the radius at a right-angle, therefore is NOT a tangent line.



let's check the third circle

\bf \textit{using the pythagorean theorem}\\\\&#10;c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}&#10;\qquad &#10;\begin{cases}&#10;c=hypotenuse\\&#10;a=adjacent\\&#10;b=opposite\\&#10;\end{cases}&#10;\\\\\\&#10;c=\sqrt{33^2+56^2}\implies c=\sqrt{4225}\implies c=\stackrel{33+32}{65}

this time, we did get our hypotenuse to 65, the triangle is a right-triangle, so the outside line is indeed a tangent line.
6 0
3 years ago
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