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prohojiy [21]
3 years ago
7

Find the least 5-digit odd number that can be formed from the digits1 2 0 3 8

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0
The answer is 1 0 2 3 8 

Glad to help :D
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Increase a price of £30 by 10%
Phoenix [80]

Answer:

£33

Step-by-step explanation:

A 10% increase is the same as multiplying a value by 1.1.

30 * 1.1 = 33

5 0
3 years ago
Read 2 more answers
Please help out need it​
juin [17]

Answer:

at the answer is about 5.29

Step-by-step explanation:

to do this u need the pythagorean theorem.

a squared+ b squared=c squared

we have the a and c values so what u would do is c squared- a squared. (8 squared - 6 squared = b squared.

8 0
3 years ago
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45 + 60 = 15 x ___ + 15 x ___
tia_tia [17]

Answer:45+60=15x+15x

Step 1: Simplify both sides of the equation.

45+60=15x+15x

(45+60)=(15x+15x)(Combine Like Terms)

105=30x

105=30x

Step 2: Flip the equation.

30x=105

Step 3: Divide both sides by 30.

30x/30= 105/30

x= 7/2

Answer:

x= 7/2

may i have brainliest please

3 0
3 years ago
What is 310,763,146 in expanded form
lesya [120]
In expanded form, the number would look like this:

300,000,000 + 10,000,000 + 700,000 + 60,000 + 3,000 + 100 + 40 + 6

When you add the value of all of these digits, it'll get you the number: 310,763,146. Adding all of these values up and getting the number you originally started with is a great method of making sure you got the right answer.
6 0
3 years ago
This is my last question can someone help me with my homework.
shutvik [7]

9514 1404 393

Answer:

  C, A, A

Step-by-step explanation:

In general, you ...

  • identify the coefficients of one of the variables
  • swap them, and negate one of them
  • multiply the corresponding equations by the "adjusted" coefficients.

__

In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

  multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

  multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

__

The other problems are worked in a similar fashion.

8 0
3 years ago
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