Answer:
£33
Step-by-step explanation:
A 10% increase is the same as multiplying a value by 1.1.
30 * 1.1 = 33
Answer:
at the answer is about 5.29
Step-by-step explanation:
to do this u need the pythagorean theorem.
a squared+ b squared=c squared
we have the a and c values so what u would do is c squared- a squared. (8 squared - 6 squared = b squared.
Answer:45+60=15x+15x
Step 1: Simplify both sides of the equation.
45+60=15x+15x
(45+60)=(15x+15x)(Combine Like Terms)
105=30x
105=30x
Step 2: Flip the equation.
30x=105
Step 3: Divide both sides by 30.
30x/30= 105/30
x= 7/2
Answer:
x= 7/2
may i have brainliest please
In expanded form, the number would look like this:
300,000,000 + 10,000,000 + 700,000 + 60,000 + 3,000 + 100 + 40 + 6
When you add the value of all of these digits, it'll get you the number: 310,763,146. Adding all of these values up and getting the number you originally started with is a great method of making sure you got the right answer.
9514 1404 393
Answer:
C, A, A
Step-by-step explanation:
In general, you ...
- identify the coefficients of one of the variables
- swap them, and negate one of them
- multiply the corresponding equations by the "adjusted" coefficients.
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In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:
multiply equation 2 by -4 . . . (eliminates x)
Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:
multiply equation 1 by 3 . . . (eliminates y)
These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.
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The other problems are worked in a similar fashion.