Answer:
22.38 g of silicone-32 will be present in 300 years.
Step-by-step explanation:
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by
where,
= quantity of the substance remaining
= initial quantity of the substance
= time elapsed
= half life of the substance
From the information given we know:
- The initial quantity of silicone-32 is 30 g.
- The time elapsed is 300 years.
- The half life of silicone-32 is 710 years.
So, to find the quantity of silicone-32 remaining we apply the above equation
22.38 g of silicone-32 will be present in 300 years.
LCD (1/7, 14/7, 12/13, 5/6)
LCM = (7, 7, 13, 6)
= 2 * 3 * 7 * 13
= 546
1/7 = 78/546
14/7 = 1092/546
12/13 = 504/546
5/6 = 455/546
Calculation:
1/7 + 14/7
= 1 + 14/7
= 15/7
The common denominator you can calculate as the least common multiple of the both denominators: LCM (7, 7) = 7
Add:
15/7 + 12/13
= 15 . 13/7. 13 + 12 . 7/13 . 7
= 195/91 + 84/91
= 195 + 84/91
= 279/91
The common denominator you can calculate as the least common multiple of the both denominators: LCM (7, 13) = 91
Add:
279/91 + 5/6
= 279 . 6/91 . 6 + 5 . 91/6. 91
= 1674/546 + 455/546
= 1674 + 455/546
= 2129/546
The common denominator you can calculate as the least common multiple of the both denominators: LCM (91, 6) = 546
Hence, 546 is the LCM/LCD of (1/7, 14/17, 13/13, 5/6).
Hope that helps!!!!!!
Answer:
65,760
Step-by-step explanation:
move decimal over two places to make a percent a decimal so .37
then multiply that times the 48000 to get 17,760 and then add that to the original 48000 to get 65,760
Answer:
Step-by-step explanation:
it is not.
