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melomori [17]
3 years ago
6

[HTML]What is a counterexample for the statement "If all four sides of a quadrilateral

Mathematics
2 answers:
fredd [130]3 years ago
8 0

Answer:

"the quadrilateral must be a rhombus"

this is right

Step-by-step explanation:

A counterexample is a statement that proves a conjecture false.

Marysya12 [62]3 years ago
5 0

Answer:

the quadrilateral must be a rhombus

Step-by-step explanation:

your welcome

i guess a got it right bit i got a 100 on the quiz

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makvit [3.9K]
The answer would be c
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3 years ago
3x-1 and 5x+2 find the area
Alex787 [66]

Answer:

=  15 {x}^{2}  + x - 2 \\

Step-by-step explanation:

(3x - 1) \times (5x + 2) \\ 3x(5x + 2 ) - 1(5x + 2) \\ 15 {x}^{2}  + 6x - 5x - 2 \\ =  15 {x}^{2}  + x - 2

hope this helps

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3 years ago
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WHAT IS THE SOLUTION TO 5-2N= 17
ryzh [129]
N is equal to 11 because 5-2n=17 would be changed into 2n-5=17 because it would be -17 if it was the original problem so that is why 

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3 years ago
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Can someone help mr in this multi answer question
Oksana_A [137]

Answer:

A, C and D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y - intercept )

here m = - 3, thus

y = - 3x + c ← is the partial equation

To find c substitute (- 1, 4) into the partial equation

4 = 3 + c ⇒ c = 4 - 3 = 1

y = - 3x + 1 ← in slope- intercept form → C

Add 3x to both sides

3x + y = 1 ← in standard form → A

-----------------------------------------------------------

The equation of a line in slope- intercept form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = - 3 and (a, b) = (- 1, 4), thus

y - 4 = - 3(x + 1) ← in point- slope form → D

3 0
3 years ago
At 10:00 AM a truck started traveling from point A with a speed of 40mph. 3 hours and 10 minutes later a car started to drive fr
maks197457 [2]

Answer:

12:07 pm

Step-by-step explanation:

The question is on relative speed

<u>Calculate the distance covered by truck after 3hours and 10 minutes</u>

Given; speed of truck= 40mph

Time the truck took to travel before the car started to drive from point A= 3h 10 minutes

Change hours to minutes= (60×3) + 10 = 190 minutes

Formulae for speed, S=d/t where S is speed of truck, d is distance covered and t is time

if S=d/t then distance d=S×t

d= 40×190/60 =380/3 =126.67 miles

<u>Finding the time the car catch up with the truck</u>

t=d/S where d=126.67 miles and speed of car = 60mph

t= 126.67/60 = 2.11 hours

Change hours to minutes

1 hr=60minutes

2.11 hrs= 2.11×60=126.67 minutes⇒2hrs and 6.67 minutes

t⇒2 hrs 7minutes

Add to the departure  time

10.00 + 2: 07 = 12:07 pm

7 0
3 years ago
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