X = -3.
The distance from p(-9, 0, 0) is
d = sqrt((x+9)^2 + y^2 + z^2)
The distance from q(3,0,0) is
d = sqrt((x-3)^2 + y^2 + z^2)
Let's set them equal to each other.
sqrt((x+9)^2 + y^2 + z^2) = sqrt((x-3)^2 + y^2 + z^2)
Square both sides, then simplify
(x+9)^2 + y^2 + z^2 = (x-3)^2 + y^2 + z^2
x^2 + 18x + 81 + y^2 + z^2 = x^2 - 6x + 9 + y^2 + z^2
18x + 81 = - 6x + 9
24x + 81 = 9
24x = -72
x = -3
So the desired equation is x = -3 which defines a plane.
Uhhh i think the answers A
Answer:
83.25
Step-by-step explanation:
add all the numbers and divide by 8. 666/8 = 83.25
Subtract (1/3)x from both sides, you get: (1/3)x+6=-13
subtract 6 from both sides, you get (1/3)x=-19
multiple 3 on both sides, you get x=-57
x=-57 is the answer.
