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3 years ago

10

The upper quartile for the data set given below is . 14, 8, 23, 9, 11, 27, 22, 3, 17, 12, 29

1 answer:

sdas [7]3 years ago

6 0

The upper quartile is 23

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Write the equation of the perpendicular bisector of . Point B is located at (–3, 1), and point C is located at (1, 5).

maxonik [38]

The equation of perpendicular bisector of BC is

$y=-x+2$

Further explanation:

A perpendicular bisector passes through the mid-point of a line so to get an ordered pair from which the perpendicular bisector will pass we need to find the mid-point of BC.

$Mid-point = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2} )\\Here\\(x_1,y_1) = (-3,1)\\(x_2,y_2) = (1,5)\\Putting\ values\ in\ formula\\M = (\frac{-3+1}{2} , \frac{1+5}{2} )\\= (\frac{-2}{2} ,\frac{6}{2})\\= (-1, 3)$

So the perpendicular bisector will pass through (-1,3)

Let m1 be the slope of BC

Then

$m_1 = \frac{y_2-y_1}{x_2-x_1} \\=\frac{5-1}{1+3} \\=\frac{4}{4}\\ =1$

Let m2 be the slope of perpendicular bisector

We know that the product of slopes of perpendicular lines is -1.

$m_1.m_2 = -1\\1*m_2 = -1\\m_2 = -1$

The standard form of point-slope form of line is:

$y=mx+b$

Putting the value of slope of bisector we get

$y=(-1)(x)+b\\y=-x+b$

To find the value of b, put the ordered pair (-1,3) in the equation

$3 = -(-1) +b\\3= 1+b\\3-1 =b\\b=2\\$

Putting the values of m and b in standard form

$y=-x+2$

Hence the equation of perpendicular bisector of BC is

$y=-x+2$

Keywords: Perpendicular bisector, Point-slope form

Learn more about point-slope form at:

#LearnwithBrainly

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3 years ago

Plz help <br> Dana sells tomatoes

insens350 [35]

Answer:

4

Step-by-step explanation:

6 0

3 years ago

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Round to the nearest hundredth : 5.992

denis23 [38]

Answer:

6

Step-by-step explanation:

8 0

3 years ago

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Help me with these math questions....

Nady [450]

Answer: cotθ

<u>Step-by-step explanation:</u>

tanθ * cos²θ * csc²θ

= $\dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}$

= $\dfrac{cos\theta}{sin\theta}$

= cotθ

Answer: B

<u>Step-by-step explanation:</u>

The parent graph is y = x²

The new graph y = -x² + 3 should have the following:

reflection over the x-axis
vertical shift up 3 units

Answers:

a. Quadrant II
b. negative
c. $\dfrac{\pi}{6}$
d. C
e. $-\dfrac{\sqrt{3}}{3}$

<u>Explanation:</u>

$\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}$

a) Quadrant 2 is: $\dfrac{\pi}{2} < \theta < \pi$

b) In Quadrant 2, cos is negative and sin is positive, so tan is negative

c) $\pi-\dfrac{5\pi}{6}$ = $\dfrac{\pi}{6}$

d) the reference line is above the x-axis so it is negative --> $-tan\dfrac{\pi}{6}$

e) $tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}$

4 0

2 years ago

The angle of elevation from a point 25 feet from the base of a tree on level ground to the top of the tree is 30°. Find the heig

xz_007 [3.2K]

The answer is C it won’t let me do all the steps but I hope it helps

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2 years ago

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