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son4ous [18]
3 years ago
11

Name an artist that helped pioneer Country Gospel

Advanced Placement (AP)
1 answer:
Montano1993 [528]3 years ago
5 0
Sister Rosetta
Kirk Franklin
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What is the distance between A and B on the number line below? 0.55 0.65 2.48 4.85
jek_recluse [69]

Answer:

0.55

Explanation:

cause look on the chart and count how many spaces and it led it up to this 0.55

3 0
3 years ago
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compare the social system of europe from the period 400-1450 to those of south asia. Give one similarity and one difference. ASA
Strike441 [17]
The similarity between the social system is the hierarchy that created in society based on the job that held by individuals.
The main difference is the openness. South Asian culture directly acknowledge the discrimination while the European culture masked it even though the nobles held all the power in the society.
7 0
3 years ago
1. The rate at which people enter a movie theater on a given day is modeled by the function S defined by S(t) = 80 -12 cos 6 The
Arlecino [84]

Hi there!

a.

To find the total amount of people that have ENTERED by t = 20, we must take the integral of the appropriate function.

\text{Amount that entered} = \int\limits^{20}_{10} {S(t)} \, dt \\\\ = \int\limits^{20}_{10} {80 - 12cos(\frac{t}{5})} \, dt

Evaluate using a calculator:

= 899.97 \approx \boxed{900\text{ people}}

b.

To solve, we can find the total amount of people that have entered of the interval and subtract the total amount of people that have left from this value.

In other terms:
\text{Amount of people} = \int\limits^{20}_{10} {S(t)} \, dt - \int\limits^{20}_{10} {R(t)} \, dt

We can evaluate using a calculator (math-9 on T1-84):


\text{\# of people} = \int\limits^{20}_{10} {80-12cos(\frac{t}{5})} \, dt - \int\limits^{20}_{10} {12e^{\frac{t}{10}}+20} \, dt

= 899.97 - 760.49 = 139.47 \approx \boxed{139 \text{ people}}

c.

If:
P(t) = \int\limits^t_{10} {S(t) - R(t)} \, dt

Then:

\frac{dP}{dt}  = P'(t)= \frac{d}{dt}\int\limits^t_{10} {S(t) - R(t)} \, dt  = S(t) - R(t)

Evaluate at t = 20:


S(20) = 80 - 12cos(\frac{20}{5}) = 87.844\\\\R(20) = 12e^{\frac{20}{10}} + 20 = 108.669

S(20) - R(20) = 87.844 - 108.669 = -20.823

This means that at t = 20, there is a <u>NET DECREASE</u> of people at the movie theater of around 20.823 (21) people per hour.

d.

To find the maximum, we must use the first-derivative test.

Set S(t) - R(t) equal to 0:

80 - 12cos(\frac{t}{5}) - 12e^{\frac{t}{10}} - 20 = 0\\\\60 - 12(cos(\frac{t}{5}) + e^{\frac{t}{10}})= 0

Graph the function with a graphing calculator and set the function equal to y = 0:

According to the graph, the graph of the first derivative changes from POSITIVE to NEGATIVE at t ≈ 17.78 hours, so there is a MAXIMUM at this value.

<u>Thus, at t = 17.78 hours, the amount of people at the movie theater is a MAXIMUM.</u>

8 0
2 years ago
In a class, there are 18 girls and 14 boys. If the teacher selects two students at random to attend a party with the principal,
Vikki [24]

number of different pairs the teacher can choose= nCr (18+14, 2)=496

no. of opposite gender pairs possible= 14 (since there are only 14 boys)

probability = 14/496= 7/248

6 0
3 years ago
Read this passage from an article about the job of a circus ringmaster.
Nikolay [14]

Answer:

C. It's the ringmasters job to hold the show together. if something hour goes wrong they try there best to stall for time.

4 0
3 years ago
Read 2 more answers
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