Answer:
(a) 2 feet.
(b) 2 feet.
Step-by-step explanation:
We have been given that the velocity function 
in feet per second, is given for a particle moving along a straight line.
(a) We are asked to find the displacement over the interval 
.
Since velocity is derivative of position function , so to find the displacement (position shift) from the velocity function, we need to integrate the velocity function.
Using power rule, we will get:
![\left[\frac{t^{-\frac{1}{2}+1}}{-\frac{1}{2}+1}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%7B-%5Cfrac%7B1%7D%7B2%7D%2B1%7D%7D%5Cright%5D%20%5E4_1)
![\left[\frac{t^{\frac{1}{2}}}{\frac{1}{2}}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B%5Cfrac%7Bt%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%5Cright%5D%20%5E4_1)
![\left[2t^{\frac{1}{2}}\right] ^4_1](https://tex.z-dn.net/?f=%5Cleft%5B2t%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5Cright%5D%20%5E4_1)
Therefore, the total displacement on the interval would be 2 feet.
(b). For distance we need to integrate the absolute value of the velocity function.
Since square root is not defined for negative numbers, so our integral would be .
We already figured out that the value of is 2 feet, therefore, the total distance over the interval would be 2 feet.
Rise: 8 Run: -2
8/2
Have a nice day!
Step-by-step explanation:
In ️ BEA and ️ CED
EB=EC ----given
angle ABE= angle DCE --------- given
angle DEB= angle DCE -------vertically opposite angles are equal
Hence, ️ BEA is congruent to ️ CED
Answer:
= 1.80909 × 104
(scientific notation) (MOST COMMON)
Step-by-step explanation:
= 1.80909 × 104
(scientific notation)
= 1.80909e4
(scientific e notation)
= 18.0909 × 103
(engineering notation)
(thousand; prefix kilo- (k))
= 18090.9
(real number)
Please mark this as brainliest, it would help a lot
Answer:1.5
Step-by-step explanation:
12.6j + 8 = 10.2j +4.4
2.4j=3.6
j=3.6/2.4= 1.5
