The value of p+q = 403,For the given complex number a+bi and 
where p and q are co-primes
F(z)= (a+ib)z⇒this is equidistant from "0" and "z"
Given modulus of complex number (a+ib) = 10 ; p and q ∈Z
G.C.D of ( p and q)=1
(a+ib)z equidistant from "0" and "z"
p = 399 and q= 4
p+q= 399+4
p+q=403
Hence the value of p+q = 403
Complete question:A function f is defined on the complex number by f (z) = (a + bi)z, where 'a' and 'b' are positive numbers. This function has the property that the image of each point in the complex plane is equidistant from that point and the origin. Given that |a+bi|=8 and that where p and q are coprime. Find the value of (p+q)
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The area of the region = area of the two rectangles = 64 units².
<h3>How to Find the Area of Rectangles?</h3>
A rectangle has a length and a width, and its area can be calculated using the formula below:
area of rectangle = (length)(width).
The region shown is composed of two rectangles. To find the area of the region, calculate the area of each of the rectangles in the image given.
Area of rectangle 1 = (length)(width)
Length = 12 units
Width = 4 units
Area of rectangle 1 = (12)(4)
Area of rectangle 1 = 48 units²
Area of rectangle 2 = (length)(width)
Length = 4 units
Width = 4 units
Area of rectangle 2 = (4)(4)
Area of rectangle 2 = 16 units²
The area of the region = area of the two rectangles = 48 + 16 = 64 units²
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4 + 5 = 9
£180 / 9 = £20
£20 x 4 = £80
£20 x 5 =£100
Answer:
£80 : £100
hope it helped :)
