Answer:
h, j2, f, g, j1, i, k, l (ell)
Step-by-step explanation:
The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).
We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).
The horizontal asymptotes are ...
- h(x): 16x/(-4x) = -4
- j1(x): 2x^2/x^2 = 2
- i(x): 3x/x = 3
- l(x): 15x/(2x) = 7.5
- g(x): x^2/x^2 = 1
- j2(x): 3x^2/-x^2 = -3
- f(x): 0x^2/(12x^2) = 0
- k(x): 5x^2/x^2 = 5
So, the ordering least-to-greatest is ...
h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)
I think the answer is B not sure though
Answer:
125
Step-by-step explanation:
-125 x -1
Answer:
0.0786
Step-by-step explanation:
It is given that Bartholemew had drawn the replacement of 160 tickets.
There are five tickets = [0, 0, 0, 1, 2]
Now we need to find the estimate of the ticket that has 1 on it and it turns up on the 32 draws exactly.
Since the probability of the drawing 1 out of 5 tickets is given by, 
So the binomial with the parameter of n = 160 and p = 0.2, we get
P (it turns up on exactly 32 draws) = P(X = 32)
Therefore,
= 0.0786
Rise over run: I counted 3 units up and then 2 times to the right which makes the slope 3/2.
