Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
Solve for b means isolate b:
V = bh
V/h = b
Answer:
b = V/h
Answer:
-7
Step-by-step explanation:
20 - 3 (-5 + 2)^2
20 - 3 (-3)^2
20 - 3(9)
20 - 27
-7
Do you remember the special case of factoring the difference of 2 squares ?
x² - 5 = (x + √5) (x - √5)
That will be zero if either factor is zero.
First factor:
x + √5 = 0
<u>x = -√5</u>
Second factor:
x - √5 = 0
<u>x = √5</u>
===================================
Another way to look at it is just to sit there and LOOK at it.
<u>x² - 5 = 0</u>
x² = 5
This is true if x = + or - √5 .
X is tome age am x+8 is janes age