3 years ago

Help (5a-3a^3)*(4a-1)

Mathematics

1 answer:

ivann1987 [24]3 years ago

3 0

Answer:

$-12a^{4} + 3a^{3} + 20a^{2} -5a$

Step-by-step explanation:

$(5a-3a^{3} )$ • $(4a-1)$

Let's use FOIL (first, outer, inner, last) to solve this. We'll multiply the terms by one another in that fashion.

$20a^{2} - 5a - 12a^{4} + 3a^{3}$

Rearrange in decreasing exponents.

$-12a^{4} + 3a^{3} + 20a^{2} -5a$

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Likurg_2 [28]

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3 years ago

Find the x-coordinates where f ' (x)=0 for f(x)=2x+sin(4x) in the interval [0, pi]

MAVERICK [17]

Answer:

The x-coordinate is \dfrac{\pi}{6}[/tex].

Step-by-step explanation:

We are given a function f(x) as:

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so on comparing our equation with equation (1) we obtain:

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Hence, the x-coordinates where $f'(x)=0$ for $f(x)=2x+\sin(4x)$ is $\dfrac{\pi}{6}$ .

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3 years ago

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Answer:

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ryzh [129]

Answer:

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