Can somebody help me please ?? :) Thank u if u do

Determine the slope of the line.

Akimi4 [234]

Answer:

2

Step-by-step explanation:

→ Find 2 points from the line

( 0 , 6 ) and ( - 3 , 0 )

→ Find the change in y coordinates

0 - 6 = -6

→ Find the change in x coordinates

-3 - 0 = -3

→ Divide the 2 results

-6 ÷ -3 = 2

7 0

1 year ago

Can someone help me and show how to write the perimeter equation to find x.

disa [49]

Answer:

a) 10x + 8 = 21

b) x = 1.3

Step-by-step explanation:

The line of symmetry is a vertical line that passes through point C.

That makes sides BC and CD congruent, and sides AB and ED congruent.

perimeter = AB + BC + CD + DE + EA

perimeter = 2x + 3 + x + 1 + x + 1 + 2x + 3 + 4x = 10x + 8

perimeter = 21

a) Equation:

10x + 8 = 21

b)

10x + 8 = 21

10x = 13

x = 1.3

7 0

3 years ago

Evaluate the expression \dfrac{5\cdot x^3}{x^2} x 2 5⋅x 3 start fraction, 5, dot, x, cubed, divided by, x, squared, end fracti

Fantom [35]

Answer:

10

Step-by-step explanation:

Given the expression:

(5 * x³) / x² ; for x = 2

Simplifying (5 * x³) / x²

5 * x^(3-2)

5 * x^1

= 5x

For x = 2

5x = 5*2 = 10

8 0

2 years ago

Prove that the triangle EDF is isosceles. Give reasons for your answer.

Gekata [30.6K]

Answer:

$\triangle EDF$ is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are given the following things:

$\angle EDF = y$

$\text{External }\angle DFG = 90 +\dfrac{y}{2}$

Let us try to find out $\angle E$ and $\angle DFE$ . After that we will compare them.

Finding  $\angle DFE$ :

Side EG is a straight line so $\angle GFE = 180$

$\angle GFE$ is sum of internal $\angle DFE$ and external $\angle DFG$

$\angle GFE = 180 = \angle DFE + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)$

Finding  $\angle E$ :

Property of external angle: External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external $\angle DFG$ = $\angle E + \angle EDF$

$\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2} -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)$

Comparing equations (1) and (2):

It can be clearly seen that:

$\angle DFE = \angle E =90-\dfrac{y}{2}$

The two angles of $\triangle EDF$ are equal hence $\triangle EDF$ is isosceles.

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B4%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1" title=" \fra

Gnesinka [82]

Answer:

5/4

Step-by-step explanation:

You just need to multiply 1/2 by 2 to give you a common denominator:

3/4+2/4

From there you can add the numerators:

5/4

HTH :)

5 0

2 years ago