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jekas [21]
3 years ago
5

What is the probability of drawing a face card from a standard deck of cards and rolling a 3 or more on a 20-sided dice?

Mathematics
1 answer:
Nastasia [14]3 years ago
3 0

Answer: 20.77%

Step-by-step explanation:

There are 52 cards in a standard deck. Out of these cards, there are 12 face cards. Thus, the probability of drawing a face is 12/52.

On a 20-sided dice, there are 20 options of numbers to roll. Out of these 20 numbers, 18 of the numbers are greater than or equal to 3, making the probability 18/20, or 9/10.

To find the probability of two events, you need to multiply the probabilities together. Thus, you need to multiply 12/52 by 9/10.

(12/52) * (9/10) = 27/130

27/130 is about equal to 0.2077, or a 20.77% probability.

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If tu=18 and u=11 what is tv
yuradex [85]

If the point U is between points T and V, then the numerical length of TV is 29 units

<h3>How to determine the numerical length of segment TV?</h3>

From the question, we have the following lengths that can be used in our computation:

  • Length TU = 18 units
  • Length UV = 11 units

The above parameters and representations implies that the point U is between endpoints T and V

This also means that the length TV is longer than the other lengths TU and TV

So, we have the following length equation

TV = TU + UV

Substitute the known values in the above equation

So, we have the following equation

TV = 18 + 11

Evaluate the sum of the like terms in the above equation

So, we have the following equation

TV = 29

Hence, the numerical length of segment TV is 29 units

Read more about lengths at

brainly.com/question/19131183

#SPJ1

<u>Possible question</u>

If tu = 18 and uv = 11 what is tv, if point u is between points t and v

8 0
1 year ago
Plz help fast!!
Leto [7]

Answer:

D. 16 km

Step-by-step explanation:

Hope this helps!

6 0
3 years ago
Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi
Dovator [93]

Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?

Answer:

a) mean = 18

Standard deviation =3

b) low range = 12

High range = 24

c) The result of 33 girls is significantly high. Yes, the method is effective.

Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = \sqrt{npq}

= \sqrt{np(1-p)}

= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

8 0
3 years ago
Disney held a breakfast for parents and their children to eat with Mickey and Minnie MouseAdult tickets cost $17.95 and children
ratelena [41]
This is a problem for 2 equations and 2 unknown.
so let x be the number of adults in the breakfast
y be the number of children present in the breakfast

so the total people attended is 500, in equation form
x + y = 500

and the total sales made by disney is $ 7355, in equation
17.95x + 12.95y = 7355

so we can solve the equation simultaneously so solve for the values of x and y

so the number of adults at the breakfast x = 176 adults and y = 324 children 
5 0
3 years ago
Which THREE pairs of measurements are possible side lengths for a 30-60-90 triangle?
9966 [12]

Answer:

1, 5 and 6.

Step-by-step explanation:

The sides of this triangles has lengths in the ratio x : √3x : 2x where 2x is the hypotenuse.

When C = 30,  the side AB is the small leg  (=x).

When B = 90, the hypotenuse is  AC ( =2x).

When A =  60, the larger leg is BC (=√3x).

1.  AB = 4, BC = 4√3 :- Are possible legs.

5 AB = 7, AC = 14. :-  AB = small leg, AC = hypotenuse.

6. AB = 11, BC = 11√3:-   AB = small, BC = larger leg.

4 0
3 years ago
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