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tia_tia [17]
3 years ago
8

I need a answer fast please!

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0
Rewrite it without stem-and-leaf:

16,18,23,26,26,34,37,37,40,41,46

MEAN =∑(16,18,23,26,26,34,37,37,40,41,46)/11
MEAN =(16+18+23+25+26+34+37+37+40+41+46)/11 =343/11 = 31.18

MEDIAN (CENTRAL VALUE) = 34 (EQUIDISTANT FROM THE 2 EXTRENITIES)

MODE = THE HIGHEST FREQUENCY OF A NUMBER: only 34 appear twice, then the MODE is 34 that appears 2 times

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The length of a diagonal of a square is 35√2 millimeters. find the perimeter of the square
Volgvan

Answer:

i dk sorry

Step-by-step explanation:

4 0
3 years ago
Solve for b. Put your answer in simplest radical form. Show Steps plz!<br><br><br> A = 4πbc + πb^2
sladkih [1.3K]

Answer:

b = -2c ± [√(4π²c² + πA)]/π

Step-by-step explanation:

A = 4πbc + πb^2

A = 4πbc + πb²

πb² + 4πbc - A = 0

Using the quadratic formula to solve this quadratic equation.

The quadratic formula for the quadratic equation, pb² + qb + r = 0, is given as

b = [-q ± √(q² - 4pr)] ÷ 2p

Comparing

πb² + 4πbc - A = 0 with pb² + qb + r = 0,

p = π

q = 4πc

r = -A

b = [-q ± √(q² - 4pr)] ÷ 2p

b = {-4πc ± √[(4πc)² - 4(π)(-A)]} ÷ 2π

b = {-4πc ± √[16π²c² + 4πA]} ÷ 2π

b = (-4πc/2π) ± {√[16π²c² + 4πA] ÷ 2π}

b = -2c ± [√(4π²c² + πA)]/π

Hope this Helps!!!

4 0
3 years ago
find the Taylor Series for tan−1(x) based at 0. Give your answer using summation notation and give the largest open interval on
enyata [817]

Let f(x)=\tan^{-1}x. Then f'(x)=\frac1{1+x^2}. Note that f(0)=0.

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n

This means that for |-x^2|=|x|^2, or -1, we have

\displaystyle f'(x)=\frac1{1+x^2}=\frac1{1-(-x^2)}=\sum_{n\ge0}(-x^2)^n=\sum_{n\ge0}(-1)^nx^{2n}

Integrate the series to get

f(x)=f(0)+\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

\implies\tan^{-1}x=\displaystyle\sum_{n\ge0}\frac{(-1)^n}{2n+1}x^{2n+1}

6 0
3 years ago
A sales person earns a commission based on the number and type of vehicle sold. A person selling 6 cars and 3 trucks earns 4,800
AURORKA [14]
Assign variables to you unknowns.

c = $ cars
t = $ trucks

6c + 3t = 4800
8c + t = 4600

use substitution or elimination to solve the system of equations.

using elimination.. multiply second equation by -3 and add to the other to combine equations into one.

6c + 3t = 4800
-3(8c + t = 4600)
---------------------------
-18c + 0 = -9000
c = 9000/18
c = 500 $

use this in one of the equations to find the cost of a truck.

8(500) + t = 4600
4000 + t = 4600
t = 4600 - 4000
t = 600 $

question asks
2(500) + 3(600) =
1000 + 1800 = 2800 $
3 0
3 years ago
Please help, thank you
alexandr1967 [171]

Answer:

falseeeeeeeee for sure

Step-by-step explanation:

can i get brianlissssstttt

4 0
3 years ago
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