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coldgirl [10]
2 years ago
15

If 20 machines produce 1,240 printers in a day,

Mathematics
1 answer:
d1i1m1o1n [39]2 years ago
7 0

Answer:

12 machines

Step-by-step explanation:

The production rate per machine is 1240/20 = 62

For 1,984 printers it would take 32 machines (1984/62 = 32)

32 needed minus the 20 they already have means they need 12 more machines.

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This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t
mariarad [96]

Answer:

a. \frac{35}{51}

b. \frac{51}{100}

c. \frac{1}{5}

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C')  + n(B∩C')  + n(C∩C')  = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}

b. The proportion of municipal bonds are issued by cities = \frac{n(C')}{x}

=\frac{0.51x}{x}

=\frac{51}{100}

c. The proportion of municipal bonds are issued by suburbs = \frac{n(S)}{x}

=\frac{0.20x}{x}

=\frac{20}{100}

=\frac{1}{5}

3 0
2 years ago
A peregrine falcon can fly 322 kilometers per hour. How many meters per hour can the falcon fly
erma4kov [3.2K]
<span>322,000 meters. Because there is 1,000 meters in a kilometer.</span>
3 0
3 years ago
The promising alternative energy sources currently under development are fuel cell technology and large-scale solar energy power
Mumz [18]

Answer:

Step-by-step explanation:

a) Denote the event of commercially availability of f_uel cell technology as F_, commercial availability of solar power technology as S

Write the probability of energy supplied by these energy sources in the next 10 years  

P(energy supplied) = P(S ∪ F) -----(1)

Rewrite eqn (1)

P(energy supplied) = P(S) + P(F) - P(F) P(S) ----(2)

substitute 0.85 for P(S) and 0,7 for P(F) in eqn (2) to find the probability of energy supplied by these energy sources

P(energy supplied) = 0.85 + 0.7 - (0.7 * 0.85)

= 0.85 + 0.7 - (0.595)

= 1.55 - 0.595

= 0.955

Therefore, the probability that there will be energy supplied by these two alternative sources in the next 10 years is 0.955

B) write the probability of only one source of energy available

P(only one source of energy available) = P(\bar F S) ∪ P( \bar S F) ---(3)

Rewrite the equation (3)

P(only one source of energy available) =

=P(\bar F S)+P(\bar S F)\\\\=\{[1-P(F)]P(S)+[1-P(S)]P(F)\}---(4)

=\{[1-0.7]0.85+[1-0.85]0.7\}\\\\=0.255+0.105\\\\=0.36

Therefore,The probability that only one of the two alternative energy sources will be commercially viable in the next 10 years is 0.36

4 0
2 years ago
Graph a line with a slope of 3/4that contains the point (2, -3)
Jet001 [13]
Start at the point (2, -3) and then go up 3 and to the right 4 a few points and then go down 3 and to the left 4 a few points and then from there you can get an equation out of it
8 0
3 years ago
2+3+3==2=2=3=hiokwfqndklmDnkldgn
bonufazy [111]

Answer:

actually it's 234

brainliest this was hard

Step-by-step explanation:

3 0
2 years ago
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