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irina1246 [14]
2 years ago
11

System of Equations: Solve for (x,y) given the system of linear equations "X 1 point

Mathematics
1 answer:
Elenna [48]2 years ago
8 0

Answer:

  (x, y) = (4, 0)

Step-by-step explanation:

It looks like you want to solve ...

  • x - y = 4
  • x + y = 4

Adding the two equations gives ...

  2x = 8

  x = 4 . . . . divide by 2

Then ...

  y = 4 - x = 0

The solution is (x, y) = (4, 0).

_____

If you think about what you're seeing when you read the equations, you realize that adding or subtracting y gives the same result. Hence y=0 and x=4.

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Product rule:

\dfrac{\mathrm d}{\mathrm dx}(x^2e^x\log x)

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Power rule:

\dfrac{\mathrm d(x^2)}{\mathrm dx}=2x

The exponential function is its own derivative:

\dfrac{\mathrm d(e^x)}{\mathrm dx}=e^x

Assuming the base of \log x is e, its derivative is

\dfrac{\mathrm d(\log x)}{\mathrm dx}=\dfrac1x

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y=\log_bx\implies x=b^y=e^{y\ln b}\implies1=e^{y\ln b}\ln b\dfrac{\mathrm dy}{\mathrm dx}

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\implies\dfrac{\mathrm d(\log_bx)}{\mathrm dx}=\dfrac1{x\ln b}

So we end up with

2xe^x\log x+x^2e^x\log x+\dfrac{x^2e^x}x

=xe^x(2\log x+x\log x+1)

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3 years ago
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Answer:

10*15= 150

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Step-by-step explanation:


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Step-by-step explanation:


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