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mario62 [17]
3 years ago
9

Please help! Find all the missing angles ??

Mathematics
1 answer:
Natasha2012 [34]3 years ago
5 0

Answer:

A 62°

B 118°

C 62°

D 118°

E 50°

F 58°

G 120°

H 120°

I 120°

J 60°

K 60°

L 60°

M 120°

N 120°

O

P 60°

Q 35.5°

R 49°

S 35.5°

T 109°

U 71°

V 109°

W 60°

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How many solutions does the following linear equation have?<br> y = -2x -4<br> y = 1/2x - 5
Andrews [41]

Answer:

x=2/5, y=-24/5. (2/5, -24/5).

Step-by-step explanation:

y=-2x-4

y=1/2x-5

----------------

-2x-4=1/2x-5

-2x-1/2x-4=-5

-4/2x-1/2x=-5+4

-5/2x=-1

5/2x=1

x=1/(5/2)

x=2/5

y=1/2(2/5)-5

y=1/5-5

y=1/5-25/5

y=-24/5

5 0
3 years ago
Please help me with this problem! Picture Included!!
alisha [4.7K]

Answer:

y < 1

Step-by-step explanation:

graphing with inequality

6 0
2 years ago
Read 2 more answers
A pair of shoes that normally costs $75 is on sale for $55. What is the percent decrease in the price, to the
tia_tia [17]

Answer:

BI=27%

Step-by-step explanation:

x(the precentage of 55 from 75)

75x=55

x=55/75

x=0.73

55 is 0.73 of 75

0.73*100=73%

100%-73%=27%

6 0
2 years ago
Read 2 more answers
What is the slope intercept form of -11x+2y=1?
ikadub [295]

Answer:

y=  11/2 x+1/2

Step-by-step explanation:

Slope Intercept form: y = mx + b where m = slope of the line, b = y intercept and (x,y) are coordinate points on the line.

To put this in slope-intercept form, you need to solve the equation for y

-11x + 2y  =  1

<u>+11x             +11x</u>  add 11x to both sides of the equation

      <u>+2y</u> = <u>1 + 11x</u>

        2         2     Divide both sides by 2 (so y is by itself)

y = 11/2x + 1/2

6 0
3 years ago
1.What is the equation of the line perpendicular to  that passes through ? Write your answer in slope-intercept form. Show your
Juliette [100K]

Answer:

1. Use a compass to make arc marks which intersect above and below then connect.

2. y=\frac{1}{3}x + 2

Step-by-step explanation:

1. To construct a perpendicular line, use a compass to draw arc marks from one end of the segment through point P. Then repeat this again at the other end. This means at point P there will be two intersecting arc marks. Repeat the process down below with the same radius as used above. Then connect the two intersections.

2. The point slope form of a line is (y-y_1)=m(x-x_1) where x_1=-3\\y_1=1. We write  

(y-1)=m(x--3)\\(y-1)=m(x+3)  

Since the line is to be perpendicular to the line shown it will have the negative reciprocal to the slope of the function 3x+y =-8. To find m, rearrange the function to be y=-8-3x. The slope is -3 and the negative reciprocal will be 1/3.

(y-1)=\frac{1}{3}(x+3)  

Simplify for slope intercept form.

(y-1)=\frac{1}{3}(x+3)\\(y-1)=\frac{1}{3}x+1\\y=\frac{1}{3}x + 2


3 0
3 years ago
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